The vector position of a 3.70 g particle moving in the xy plane varies in time according to r₁ = (31 + 3ĵ)t + 2ĵt² where t is inseconds and r is in centimeters. At the same time, the vector position of a 5.95 g particle varies as r2 = 3î - 2ît² - 6ĵt.(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.70 s.cm =(-10.77)i + (1.06)j x cm(b) Determine the linear momentum (in g cm/s) of the system at t = 2.70 s.g. cm/sP =(c) Determine the velocity (in cm/s) of the center of mass at t = 2.70 s.cm(d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.70 s.cm/s²acmcm/s(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.70 s.μNFnet

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