A 1.90-kg particle has a velocity (2.20 1 - 4.00 ĵ) m/s, and a 4.00-kg particle has a velocity (1.00 +8.00 ĵ) m/s. (a) Find the velocity of the center of mass. Î + m/s (b) Find the total momentum of the system. Î + J kg m/s

A 1.90-kg particle has a velocity (2.20 1 - 4.00 ĵ) m/s, and a 4.00-kg particle has a velocity (1.00 +8.00 ĵ) m/s. (a) Find the velocity of the center of mass. Î + m/s (b) Find the total momentum of the system. Î + J kg m/s

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter9: Linear Momentum And Collisions

Section: Chapter Questions

Problem 10P: The magnitude of the net force exerted in the x direction on a 2.50-kg particle varies in time as...

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The vector position of a 3.50-g particle moving in the xy plane varies in time according to r1=(3i+3j)t+2jt2, where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.50 g particle varies as r2=3i2it26jt. At t = 2.50 s, determine (a) the vector position of the center of mass of the system, (b) the linear momentum of the system, (c) the velocity of the center of mass, (d) the acceleration of the center of mass, and (e) the net force exerted on the two-particle system.
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