A 2.09-kg particle has a velocity (1.90 î – 2.90 j) m/s, and a 2.95-kg particle has a velocity (0.92 î + 6.01 j) m/s. (a) Find the velocity of the center of mass. |î + i) m/s (b) Find the total momentum of the system. i) kg • m/s
A 2.09-kg particle has a velocity (1.90 î – 2.90 j) m/s, and a 2.95-kg particle has a velocity (0.92 î + 6.01 j) m/s. (a) Find the velocity of the center of mass. |î + i) m/s (b) Find the total momentum of the system. i) kg • m/s
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![A 2.09-kg particle has a velocity \( (1.90 \hat{\imath} - 2.90 \hat{\jmath}) \, \text{m/s} \), and a 2.95-kg particle has a velocity \( (0.92 \hat{\imath} + 6.01 \hat{\jmath}) \, \text{m/s} \).
(a) Find the velocity of the center of mass.
\[
(\_\_\_\_ \, \hat{\imath} + \_\_\_\_ \, \hat{\jmath}) \, \text{m/s}
\]
(b) Find the total momentum of the system.
\[
(\_\_\_\_ \, \hat{\imath} + \_\_\_\_ \, \hat{\jmath}) \, \text{kg} \cdot \text{m/s}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8caa8888-794e-4f6b-9ad1-1f5517b6770f%2Fae373f0b-a126-4e98-ac21-5aab141a0947%2F0g2qn1c_processed.png&w=3840&q=75)
Transcribed Image Text:A 2.09-kg particle has a velocity \( (1.90 \hat{\imath} - 2.90 \hat{\jmath}) \, \text{m/s} \), and a 2.95-kg particle has a velocity \( (0.92 \hat{\imath} + 6.01 \hat{\jmath}) \, \text{m/s} \).
(a) Find the velocity of the center of mass.
\[
(\_\_\_\_ \, \hat{\imath} + \_\_\_\_ \, \hat{\jmath}) \, \text{m/s}
\]
(b) Find the total momentum of the system.
\[
(\_\_\_\_ \, \hat{\imath} + \_\_\_\_ \, \hat{\jmath}) \, \text{kg} \cdot \text{m/s}
\]
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