A 2.09-kg particle has a velocity (1.90 î – 2.90 j) m/s, and a 2.95-kg particle has a velocity (0.92 î + 6.01 j) m/s. (a) Find the velocity of the center of mass. |î + i) m/s (b) Find the total momentum of the system. i) kg • m/s
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- Mechanical engineering question. Strictly don't use chatgpt. Only Handwritten allowed.1) a) Mass m1 = 0.25 kg is moving with a velocity Vr = 10 m/s and collides with mass m2 = l kg whichis at rest. After the collision, the mass m1 moves in the opposite direction with a velocity v1' = -4 m/s. What is the velocity v2', of the mass m2 subsequent to the collision?b) What is the total kinetic energy prior to the collision? What is the total kinetic energy subsequent to the collision? How much heat was generated in the collision process?A 1.95-kg particle has a velocity (1.95 î – 3.07 ĵ) m/s, and a 2.91-kg particle has a velocity (1.06 î + 5.99 ĵ) m/s. (a) Find the velocity of the center of mass. i) m/s (b) Find the total momentum of the system. |î) kg · m/s
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- What are coordinates of the center of mass for the uniform plate shown in the figure below? (x1 = 18 cm, y1 = 14 cm, and y2 = 4 cm. The figure is not shown to scale.) 10 cm 20 ст 10 cm 10 ст (a) x coordinate |(No Response) cm (b) y coordinate (No Response) cmThe figure shows a three-particle system, with masses m1 = 4.8 kg, m2 = 4,0 kg, and m3 = 6.9 kg. What are (a) the x coordinate and (b) the y coordinate of the system's center of mass? %3D y (m) mg 2 m1 x (m) (a) Number Units (b) Number i Units