The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît² – 6ĵt. 2 (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s. "cm cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s. p = g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s. cm/s cm

The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît² – 6ĵt. 2 (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s. "cm cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s. p = g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s. cm/s cm

Name: (3î + 3j)t + 2ĵt² where t is in seconds andr is in centimeters. At th
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: (3î + 3j)t + 2ĵt² where t is in seconds andr is in centimeters. At the sameThe vector position of a 4.00 g particle moving in the xy plane varies in time according tor,time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît? - 6jt.(a)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 1.76 kg particle has the xy coordinates (-1.41 m, 0.619 m), and a 5.63 kg particle has the xy…

A: m1 = 1.76 kg r1 = (-1.41 , 0.619) m m2 = 5.63 kg r2 = (0.206 , -0.607) m m3 =3 kgrc.m= (-0.848 ,…

Q: Two cars approach an ice-covered intersection. One car, of mass 1.29 x 103 kg, is initially…

A: Mass of car 1 "m1=1.29 x 10³ kg initial velocity of car 1 = V1i = 10.1 m/s. mass of car 2" m2= 1.70…

Q: Sp- Iron d₁- 2d -Midpoint Aluminum

A: Centre of mass is the point where the whole mass of the system is concentrated and the whole system…

Q: The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î…

Q: An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1 = 528 kg, m2 =…

Q: Object 1 is located at (0,1.4) m and has a mass of 79 kg. Object 2 is located at (9.4,4.1) m and…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

A: Given: Required: The velocity of the particle 4 at time t = 2.83 sec as all the…

Q: The center of mass (or center of gravity) of a two-particle system is at the origin. One particle is…

A: Center of mass lies on Origin (0,0) m1=2Kg m2=3Kg

Q: A system composed of the following particles: a 0.500 kgkg particle at the origin; a 1.25 kgkg…

A: Solution: Given that m1 = 0.5 kg (0,0) m2 = 1.25 kg (0.15m,0.2m) m3 = 0.75 kg (0.2m, -0.8m)

Q: A 46.7-kg person, running horizontally with a velocity of +4.20 m/s, jumps onto a 17.7-kg sled that…

A: Mass of person(M)=46.7kg velocity of person (vp )=4.20 m/s2 mass of sled (m)=17.7 kg initially…

Q: The figure shows a composite slab with dimensions d₁ = 11.2 cm, d₂ = 2.93 cm, and d3= 13.6 cm. Half…

Q: There particles are located at coordinates (x, y) as follow: m1 = 1.0-kg is at (0,0), m2 = 2.0 kg is…

Q: PROBLEM 1 Shown in the picture is the ammonia molecule, NH3. The hydrogens are at the corners of an…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

Q: A 4.73 kg particle has the xy coordinates (-1.50 m, 0.794 m), and a 5.13 kg particle has the xy…

A: Given that m1 = 4.73kgAnd its coordinates are (x1,y1)=(-1.50m, 0.794m)m2 = 5.13kgAnd its coordinate…

Q: The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î…

A: As per the guidelines, we are allowed to solve only 3 subparts. Since, you got the right answer for…

Q: A 3.28 kg particle has the xy coordinates (-1.46 m, 0.885 m), and a 2.47 kg particle has the xy…

A: Given information: The mass of the particle 1 (m1) = 3.28 kg The coordinates of the particle 1 (x1,…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

A: The mass of the particle 1 is 1.33 kg. The velocity of the particle 1 is 7.19 m/s+0.255 m/s2t. The…

Q: ector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î +…

A: According to bartelby guidelines only the first three sub-parts are solved. Kindly repost other…

Q: Three small but dense objects are located in the x-y plane as shown in the figure. The objects have…

Q: The vector position of a 3.70 g particle moving in the xy plane varies in time according to r₁ = (3î…

A: Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first…

Q: Three balls with masses of 3.0 kg, 1.0 kg, and 2.0 kg are located at coordinates (5.5m,5.5m),…

Q: The vector position of a 3.80g particle moving in the xy plane varies in time according tor, = (31 +…

Q: A 4.0 kg mess kit sliding on a frictionless surface explodes in two different sized parts, one has a…

A: We can calculate the original velocity by applying conservation of momentum. This states that…

Q: The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (31…

Q: A 1.82 kg particle has the xy coordinates (-1.78 m, 0.802 m), and a 4.12 kg particle has the xy…

Q: The figure shows a composite slab with dimensions d₁ = 11.9 cm, d₂ = 2.94 cm, and d3 = 12.8 cm. Half…

Q: A 3 kg asteroid is moving way out in space with velocity 3î – 2ĵ + 7k ms1. It collides with an…

A: Given data: Mass of asteroid 1 is, m1=3 kg. Velocity vector of asteroid 1 is, v1→=3i^-2j^+7k^ m/s.…

Q: Three beads are placed on the vertices of an equilateral triangle of side d = 4.1 cm. The first bead…

Q: At time t = 0, force F1 = (-6.31î + 6.70f) N acts on an initially stationary particle of mass 3.21 ×…

Q: The figure shows a cubical box that has been constructed from uniform metal plate of negligible…

Topic Video

Question

(3î + 3j)t + 2ĵt² where t is in seconds andr is in centimeters. At the same
The vector position of a 4.00 g particle moving in the xy plane varies in time according tor,
time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît? - 6jt.
(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s.
cm
cm
(b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s.
p =
g· cm/s
(c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s.
cm/s
cm
(d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.60 s.
a
cm/s?
cm
(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.60 s.
µN
net

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Trending now

This is a popular solution!

Step by step

Solved in 7 steps with 8 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

a shape is on an x-y axis, beginning at x = 0. The bottom of the shape is 25 cm long and it reaches a height of 20 cm. The shape weights 450 g. The shape has a triangular form, like a wedge. If shape has a uniform density and a uniform width in the z-direction, find the x-component of the center-of-mass.
The figure shows a composite slab with dimensions d₁ = 11.9 cm, d₂ = 2.94 cm, and d3 = 12.8 cm. Half the slab consists of aluminum (density = 2.70 g/cm³) and half consists of iron (density = 7.85 g/cm³). What are (a) the x coordinate, (b) the y coordinate, and (c) the z coordinate of the slab's center of mass? (a) Number (b) Number (c) Number dy Iron Units Units Units 2d₁ -Midpoint Aluminum dy 11
A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t1 = 2.99 s given the details for the motion of particles 1, 2, and 3. particle 1: m¡ = 1.21 kg, v1 (t) = (5.87 m/s) + (0.255 m/s?) × t particle 2: m2 = 2.69 kg, v2 (t) = (9.59 m/s) + (0.609 m/s² ) x t particle 3: m3 = 4.37 kg, V3 (t) = (7.87 m/s) + (0.153 m/s²) × t particle 4: m4 = 4.91 kg Ua = m/s
Four very thin rods, each 6.3 m long, are joined to form a square, as part (a) of the drawing shows. The center of mass of the square is located at the coordinate origin. The rod on the right is then removed, as shown in part (b) of the drawing. What are the x- and y- coordinates of the center of mass of the remaining three-rod system? ty +x +x (a) -0.75 x coordinate of the center of mass = Number Units m y coordinate of the center of mass = Number Units m
A system composed of the following particles: a 0.500 kg particle at the origin; a 1.25 kgkg particle at x = 0.150 mm, y = 0.200 mm; and a 0.750 kg particle at x = 0.200 mm, y = -0.800 mm. a. Find the x-coordinate of the center of mass of the system. b. Find the y-coordinate of the center of mass of the system.
Enet = The vector position of a 3.80 g particle moving in the xy plane varies in time according tor, = (3î + 3j)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as 2 sr, = 3î – 2ît? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.40 s. rcm 4.744i – 7.38j cm (b) Determine the linear momentum (in g• cm/s) of the system at t = 2.40 s. p = 11.4i – 35.58j g• cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.40 s. 1.245i – 3.888j cm/s = cm (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.40 s. 0.6775j cm/s? = cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.40 s. µN
Problem 3: A particle with mass ma = 3.00 kg is located at ra = (2.50 i + 3.50 j) m, and a second particle of mass m2B = 5.00 kg is located at rB = (1.50 i - 3.00 j) m. Find the location of the center of mass of the system relative to the point (1,1).
A block of mass 10.0 kg is moving east at 2.0 m/s and another block, of mass 4.0 kg is moving north at 4.0 m/s. The velocity of the center of mass of this two-block system is 2.0 m/s at an angle of 51 degrees south of east 1.8 m/s at an angle of 39 degrees north of east 6.0 m/s at an angle of 51 degrees west of north 1.8 m/s at an angle of 39 degrees east of north 2.0 m/s due west
Please Asap
A 0.346 kg puck, initially at rest on a hor- izontal, frictionless surface, is struck by a 0.275 kg puck moving initially along the r axis with a speed of 2.01 m/s. After the colli- sion, the 0.275 kg puck has a speed of 1.01 m/s at an angle of 37° to the positive x axis. Determine the magnitude of the velocity of the 0.346 kg puck after the collision. Answer in units of m/s. Answer in units of m/s. 1. 1.3422 2. 1.21901 3. 0.347028 4. 1.14264 5. 1.07153 6. 0.637653 7. 0.328271 8. 0.591588 9. 0.551494 10. 1.00165
The vector position of a 3.45 g particle moving in the xy plane varies in time according to i, - (3i + 35)t + 2jr? where t is in seconds and is in centimeters. At the same time, the vector position of a 5.20 g particle varies as i,- 31 - zir? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. x cm cm (b) Determine the linear momentum (in g cm/s) of the system at t = 2.90 s. 9. cm/s (e) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. cm/s (4) Determine the acceleration (in cm/s) of the center of mass at t = 2.90 s. cm/s? (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s. UN net
A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t1 = 2.75 s given the details for the motion of particles 1, 2, and 3. particle 1: mj = 1.33 kg, vi (t) = (7.41 m/s) + (0.277 m/s²) × t particle 2: m2 = 3.05 kg, v2 (t) = (8.05 m/s) + (0.567 m/s²) × t particle 3: m3 = 4.25 kg, v3 (t) = (6.33 m/s) + (0.195 m/s²) × t particle 4: m4 = 5.27 kg