The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît² – 6ĵt. 2 (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s. "cm cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s. p = g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s. cm/s cm

The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît² – 6ĵt. 2 (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s. "cm cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s. p = g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s. cm/s cm

Name: (3î + 3j)t + 2ĵt² where t is in seconds andr is in centimeters. At th
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: (3î + 3j)t + 2ĵt² where t is in seconds andr is in centimeters. At the sameThe vector position of a 4.00 g particle moving in the xy plane varies in time according tor,time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît? - 6jt.(a)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 1.76 kg particle has the xy coordinates (-1.41 m, 0.619 m), and a 5.63 kg particle has the xy…

A: m1 = 1.76 kg r1 = (-1.41 , 0.619) m m2 = 5.63 kg r2 = (0.206 , -0.607) m m3 =3 kgrc.m= (-0.848 ,…

Q: Sp- Iron d₁- 2d -Midpoint Aluminum

A: Centre of mass is the point where the whole mass of the system is concentrated and the whole system…

Q: The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î…

Q: The dependence of the velocity of a 3.0 kg particle on time is given by i = (8t)î+ (3t²)j in m/s…

A: Mass of particle= 3kg →v=(8t)i+(3t2)j m/s time= 2 seconds

Q: The vector position of a 3.80 g particle moving in the xy plane varies in time according to r, = (3î…

Q: Mark (60 kg) and Jay (75 kg) are on an ice pond, with Mark's location at x = -15 m and Jay at x =…

Q: An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1 = 528 kg, m2 =…

Q: Object 1 is located at (0,1.4) m and has a mass of 79 kg. Object 2 is located at (9.4,4.1) m and…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

A: Given: Required: The velocity of the particle 4 at time t = 2.83 sec as all the…

Q: A system containing two particles has a center of mass along the horizontal axis at x = 3.5 m. If…

Q: A system composed of the following particles: a 0.500 kgkg particle at the origin; a 1.25 kgkg…

A: Solution: Given that m1 = 0.5 kg (0,0) m2 = 1.25 kg (0.15m,0.2m) m3 = 0.75 kg (0.2m, -0.8m)

Q: Physics Question

Q: The figure shows a composite slab with dimensions d₁ = 11.2 cm, d₂ = 2.93 cm, and d3= 13.6 cm. Half…

Q: There particles are located at coordinates (x, y) as follow: m1 = 1.0-kg is at (0,0), m2 = 2.0 kg is…

Q: PROBLEM 1 Shown in the picture is the ammonia molecule, NH3. The hydrogens are at the corners of an…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

Q: A 4.73 kg particle has the xy coordinates (-1.50 m, 0.794 m), and a 5.13 kg particle has the xy…

A: Given that m1 = 4.73kgAnd its coordinates are (x1,y1)=(-1.50m, 0.794m)m2 = 5.13kgAnd its coordinate…

Q: The vector position of a 4.00 g particle moving in the xy plane varies in time according to r, = (3î…

A: As per the guidelines, we are allowed to solve only 3 subparts. Since, you got the right answer for…

Q: A 3.28 kg particle has the xy coordinates (-1.46 m, 0.885 m), and a 2.47 kg particle has the xy…

A: Given information: The mass of the particle 1 (m1) = 3.28 kg The coordinates of the particle 1 (x1,…

Q: Find the X coordinate (Xcom) and Y coordinate (Ycom) in meters of the center of mass of the three…

A: Given data: Three masses in xy-plane m1 = 1.0 kg at (0 m, 0 m) m2 = 3.0 kg at (1.0m, 0 m m3 = 4.0…

Q: Three small but dense objects are located in the x-y plane as shown in the figure. The objects have…

Q: The vector position of a 3.70 g particle moving in the xy plane varies in time according to r₁ = (3î…

A: Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first…

Q: A system consists of four particles located as shown. Find the x and y coordinates of the center of…

Q: Four objects are situated along the y axis as follows: 5.8 kg object is at +30 m, 21.9 kg object is…

A: Given values: Masses and respective y-co-ordinates, m1=5.8 kg, y1=30 mm2=21.9 kg, y2=25 mm3=19.4…

Q: Four objects are situated along the y axis as follows: 16.6 kg object is at +30 m, 11.9 kg object is…

Q: Three balls with masses of 3.0 kg, 1.0 kg, and 2.0 kg are located at coordinates (5.5m,5.5m),…

Q: A system consists of two particles with masses m1 = 2 kg and m2 = 3 kg. Particle 1 is located at…

A: Mass of particle 1 (m1) = 2 kgMass of particle 2 (m2) = 3 kgCoordinates of particle 1 (x1, y1) = (2…

Q: The vector position of a 3.80g particle moving in the xy plane varies in time according tor, = (31 +…

Q: The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (31…

Q: A 1.82 kg particle has the xy coordinates (-1.78 m, 0.802 m), and a 4.12 kg particle has the xy…

Q: located at (-7,-4.6)m and has a mass of 49.5 kg. Object 2 is located at (1.5,5)m and has a mass of…

A: Given m1 = 49.5 kg m2 = 64.1 kg m3 = 34.7 kg X coordinates x1 = -7 m x2 = 1.5 m x3 = -0.3 m

Q: B0 kg particle has the xy coordinates (-1.39 m, 0.366 m), and a 2.68 kg particle has the xy…

A: position of center of mass rcm = (m1 r1 +m2 r2 )/(m1 + m2 )

Q: Under many conditions, the center of mass of a system of particles can represent the system as a…

A: In this case, two identical particles traveling toward each other at the same speed.

Q: The figure shows a composite slab with dimensions d₁ = 11.9 cm, d₂ = 2.94 cm, and d3 = 12.8 cm. Half…

Q: The vector position of a 3.95 g particle moving in the xy plane varies in time according to r, = (3î…

A: Since you have asked multiple subparts, we will solve the first three for you. If you want a…

Q: Masses of m = 2 (kg) and m2 = 4 (kg), the directions of which are shown in the figure, collide…

Q: A system of four particles moves along one dimension. The center of mass of the system is at rest,…

A: Centre of mass of the system is at rest therefore the velocity of the centre of mass is zero i.e.…

Q: Determine the coordinates in which a particle of mass m4 = 6g must be placed so that the center of…

Q: The figure shows a cubical box that has been constructed from uniform metal plate of negligible…

Topic Video

Question

(3î + 3j)t + 2ĵt² where t is in seconds andr is in centimeters. At the same
The vector position of a 4.00 g particle moving in the xy plane varies in time according tor,
time, the vector position of a 5.55 g particle varies as r, = 3î - 2ît? - 6jt.
(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.60 s.
cm
cm
(b) Determine the linear momentum (in g · cm/s) of the system at t = 2.60 s.
p =
g· cm/s
(c) Determine the velocity (in cm/s) of the center of mass at t = 2.60 s.
cm/s
cm
(d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.60 s.
a
cm/s?
cm
(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.60 s.
µN
net

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Trending now

This is a popular solution!

Step by step

Solved in 7 steps with 8 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

a shape is on an x-y axis, beginning at x = 0. The bottom of the shape is 25 cm long and it reaches a height of 20 cm. The shape weights 450 g. The shape has a triangular form, like a wedge. If shape has a uniform density and a uniform width in the z-direction, find the x-component of the center-of-mass.
The figure shows a composite slab with dimensions d₁ = 11.9 cm, d₂ = 2.94 cm, and d3 = 12.8 cm. Half the slab consists of aluminum (density = 2.70 g/cm³) and half consists of iron (density = 7.85 g/cm³). What are (a) the x coordinate, (b) the y coordinate, and (c) the z coordinate of the slab's center of mass? (a) Number (b) Number (c) Number dy Iron Units Units Units 2d₁ -Midpoint Aluminum dy 11
A 1.29 kg particle has the xy coordinates (-1.25 m, 0.116 m), and a 5.32 kg particle has the xy coordinates (0.300 m, -0.345 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 2.97 kg particle such that the center of mass of the three-particle system has the coordinates (-0.308 m, -0.473 m)?
Please Help!
A set of three masses is arranged as shown below. Calculate the position of the center of mass of the system, i.e., find the coordinates (xcm, Ycm) in units of meters. У (m) 2.00 2.00 kg 5.00 kg 1.00 10.00 kg + x (m) 1.00 2.00
A system consists of three masses that are placed on a horizontal plane or x-axis. 1 kg at the origin, 2 kg at position x = 5 cm, and another 2kg at position x = 10 cm. Find the distance of the centre of mass of the system from the origin.
A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t1 = 2.99 s given the details for the motion of particles 1, 2, and 3. particle 1: m¡ = 1.21 kg, v1 (t) = (5.87 m/s) + (0.255 m/s?) × t particle 2: m2 = 2.69 kg, v2 (t) = (9.59 m/s) + (0.609 m/s² ) x t particle 3: m3 = 4.37 kg, V3 (t) = (7.87 m/s) + (0.153 m/s²) × t particle 4: m4 = 4.91 kg Ua = m/s
Four very thin rods, each 6.3 m long, are joined to form a square, as part (a) of the drawing shows. The center of mass of the square is located at the coordinate origin. The rod on the right is then removed, as shown in part (b) of the drawing. What are the x- and y- coordinates of the center of mass of the remaining three-rod system? ty +x +x (a) -0.75 x coordinate of the center of mass = Number Units m y coordinate of the center of mass = Number Units m
Mass MAMAM_A = 33 kg and massMB= 30 kg, They have velocities (in m/s) ,v→A = 12 i^ - 20 j^ and v→B = - 20 i^ + 13 j^. Part A Determine the velocity of the center of mass of the system.
A rocket ship is travelling through space. The fuselage section has a mass of 505 kg. The Nose Cone (front end) section has a mass of 100 kg. The rocket is travelling at 52.0 m/s when the rocket engine stops and the two sections are separated by an explosion in such a way that they stay in a straight line. If the Nose Cone section (front end) continues forward at 98.0 m/s, determine the speed of the Fuselage section after the separation.
Problem 3: A particle with mass ma = 3.00 kg is located at ra = (2.50 i + 3.50 j) m, and a second particle of mass m2B = 5.00 kg is located at rB = (1.50 i - 3.00 j) m. Find the location of the center of mass of the system relative to the point (1,1).
A block of mass 10.0 kg is moving east at 2.0 m/s and another block, of mass 4.0 kg is moving north at 4.0 m/s. The velocity of the center of mass of this two-block system is 2.0 m/s at an angle of 51 degrees south of east 1.8 m/s at an angle of 39 degrees north of east 6.0 m/s at an angle of 51 degrees west of north 1.8 m/s at an angle of 39 degrees east of north 2.0 m/s due west