The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (31 + 3)t + 2ĵt² where t is in seconds and is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r2 = 31 - 2ît² - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s. cm = (b) Determine the linear momentum (in g cm/s) of the system at t = 2.80 s. g. cm/s p= (c) Determine the velocity (in cm/s) of the center of mass at t = 2.80 s. → Vcm= cm acm= (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.80 s. cm/s² cm/s net = (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s. μN

The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (31 + 3)t + 2ĵt² where t is in seconds and is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r2 = 31 - 2ît² - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s. cm = (b) Determine the linear momentum (in g cm/s) of the system at t = 2.80 s. g. cm/s p= (c) Determine the velocity (in cm/s) of the center of mass at t = 2.80 s. → Vcm= cm acm= (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.80 s. cm/s² cm/s net = (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s. μN

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Description: The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and is in centimeters. At the same time, the vectorposition of a 5.65 g particle varies as r31 – 2ît² – 6ĵt.r2(a

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter6: Momentum, Impulse, And Collisions

Section: Chapter Questions

Problem 46P: A space probe, initially at rest, undergoes an internal mechanical malfunction and breaks into three...

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Question

The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and is in centimeters. At the same time, the vector
position of a 5.65 g particle varies as r
31 – 2ît² – 6ĵt.
r2
(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s.
cm
=
(b) Determine the linear momentum (in g· cm/s) of the system at t = 2.80 s.
cm
cm
(c) Determine the velocity (in cm/s) of the center of mass at t = 2.80 s.
cm
g.cm/s
net
(d) Determine the acceleration (in cm/s²) of the center of mass at t = 2.80 s.
cm/s²
=
=
cm/s
(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s.
μN

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