The vector position of a 3.30 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2jt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as r, = 3î – 2ît? – 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 3.00 s. cm "cm %3D (b) Determine the linear momentum (ing· cm/s) of the system at t = 3.00 s. g· cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 3.00 s. cm/s %3D cm (d) Determine the acceleration (in cm/s²) of the center of mass at t = 3.00 s. cm/s2 cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 3.00 s. Fnet UN

The vector position of a 3.30 g particle moving in the xy plane varies in time according to r, = (3î + 3j)t + 2jt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as r, = 3î – 2ît? – 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 3.00 s. cm "cm %3D (b) Determine the linear momentum (ing· cm/s) of the system at t = 3.00 s. g· cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 3.00 s. cm/s %3D cm (d) Determine the acceleration (in cm/s²) of the center of mass at t = 3.00 s. cm/s2 cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 3.00 s. Fnet UN

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Enet = The vector position of a 3.80 g particle moving in the xy plane varies in time according tor, = (3î + 3j)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as 2 sr, = 3î – 2ît? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.40 s. rcm 4.744i – 7.38j cm (b) Determine the linear momentum (in g• cm/s) of the system at t = 2.40 s. p = 11.4i – 35.58j g• cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.40 s. 1.245i – 3.888j cm/s = cm (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.40 s. 0.6775j cm/s? = cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.40 s. µN
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The position of a particle according to the appropriate coordinate set can be vectorially specified in meters as r = i(sin2πt) -16j(1-e-t/4) + kt2/4 where t is the movement time of particle in seconds after passing its origin. If the mass of the particle is 2,4 kg, calculate the x component of its R force and the magnitude of its resultant force R at time t = 4s.
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