The vector position of a 3.45 g particle moving in the xy plane varies in time according to , = (31 + 3)t + 2jr? where t is in seconds and F is in centimeters. At the same time, the vector position of a 5.20 g particle varies as i, - 3i - 2ir? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. x cm cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.90 s. g- cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. cm/s Cm

College Physics
11th Edition
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Chapter1: Units, Trigonometry. And Vectors
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The vector position of a 3.45 g particle moving in the xy plane varies in time
according to i, = (31 + 3j)t + 2jt? where t is in seconds and i is in centimeters. At the same
time, the vector position of a 5.20 g particle varies as i, = 31 - 2ir? - 6jt.
(a) Determine the vector position (in cm) of the center of mass of the system at t =
2.90 s.
X cm
cm
(b) Determine the linear momentum (in g · cm/s) of the system at t = 2.90 s.
g. cm/s
(c) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s.
cm/s
cm
(d) Determine the acceleration (in cm/s?) of the center of mass at t = 2.90 s.
cm/s?
cm
(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s.
F.
net
UN
Transcribed Image Text:The vector position of a 3.45 g particle moving in the xy plane varies in time according to i, = (31 + 3j)t + 2jt? where t is in seconds and i is in centimeters. At the same time, the vector position of a 5.20 g particle varies as i, = 31 - 2ir? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. X cm cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.90 s. g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. cm/s cm (d) Determine the acceleration (in cm/s?) of the center of mass at t = 2.90 s. cm/s? cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s. F. net UN
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