A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.99 s given the details for the motion of particles 1, 2, and 3. particle 1: mi = 1.33 kg, vi (1) = (6.97 m/s) + (0.365 m/s2) x t particle 2: m2 = 3.53 kg, vz (1) = (8.93 m/s) + (0.357 m/s2) xt particle 3: m3 = 4.85 kg, vz (1) = (6.77 m/s) + (0.405 m/s) x 1 particle 4: m4 = 4.91 kg
A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.99 s given the details for the motion of particles 1, 2, and 3. particle 1: mi = 1.33 kg, vi (1) = (6.97 m/s) + (0.365 m/s2) x t particle 2: m2 = 3.53 kg, vz (1) = (8.93 m/s) + (0.357 m/s2) xt particle 3: m3 = 4.85 kg, vz (1) = (6.77 m/s) + (0.405 m/s) x 1 particle 4: m4 = 4.91 kg
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 66P: Two particles of masses m1 and m2 , move uniformly in different circles of radii R1 and R2 R2 about...
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![A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do
not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.99 s given the details for
the motion of particles 1, 2, and 3.
particle 1:
m = 1.33 kg,
vi (1) = (6.97 m/s) + (0.365 m/s²) x t
particle 2:
3.53 kg, v2 (1) = (8.93 m/s) + (0.357 m/s) x t
mɔ =
particle 3:
m3 = 4.85 kg, U3 (1) = (6.77 m/s) + (0.405 m/s) × t
particle 4:
m4 = 4.91 kg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd47b3cb0-96cd-4a73-b41c-d181713d04c8%2F7af18f4f-168d-433d-9c4d-617eafb3d455%2Fbnw46dm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A system of four particles moves along one dimension. The center of mass of the system is at rest, and the particles do
not interact with any objects outside of the system. Find the velocity v4 of particle 4 at t = 2.99 s given the details for
the motion of particles 1, 2, and 3.
particle 1:
m = 1.33 kg,
vi (1) = (6.97 m/s) + (0.365 m/s²) x t
particle 2:
3.53 kg, v2 (1) = (8.93 m/s) + (0.357 m/s) x t
mɔ =
particle 3:
m3 = 4.85 kg, U3 (1) = (6.77 m/s) + (0.405 m/s) × t
particle 4:
m4 = 4.91 kg
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