The mass of particle 1 is 11kg. The initial velocity for particle 1 is  (-104m/s)i + (216m/s)j. F21 = Fxe^-(t/T) + Fysin(2pit/T). Only need help finding the displacement of particle 1 in the x and y directions.

College Physics
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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The mass of particle 1 is 11kg. The initial velocity for particle 1 is  (-104m/s)i + (216m/s)j. F21 = Fxe^-(t/T) + Fysin(2pit/T). Only need help finding the displacement of particle 1 in the x and y directions.

**Educational Content on Force and Motion:**

**Introduction:**

This example explores the dynamics of particles in motion with a given force applied. Specifically, it examines the force exerted by particle 2 on particle 1, represented mathematically by the following equation:

\[ \vec{F}_{21}(t) = F_x e^{-(t/T)} \hat{i} + F_y \sin(2\pi t/T) \hat{j} \]

where the parameters are specified as:
- \( F_x = 16.8 \, \text{N} \)
- \( F_y = -106 \, \text{N} \)
- \( T = 100 \, \text{s} \)

The time interval considered starts at \( t_i = 0 \) and ends at \( t_f = 243 \, \text{s} \).

**Key Calculations:**

The analysis involves several critical kinetic and dynamic calculations:

1. **Impulse and Force:**
   - Impulse exerted from particles in both \( x \) and \( y \) directions.
   - Average force experienced by the particles.

2. **Velocity and Momentum:**
   - Final velocities of both particles after applying the force over the given interval.
   - Momentum change in the system.

3. **Energy:**
   - Changes in kinetic energy for both particles.
   - Overall change in kinetic energy for the system.

**Detailed Calculation Example:**

**Displacement of Particle 1 in the \( x \)-direction:**

The task was to find the \( x \)-displacement of particle 1, which is calculated to be:

\[ \Delta x_1 = 19819.96363 \, \text{m} \]

Additional options to find hints or guidance on the problem are available but not specified here.

This example provides an illustrative scenario for exploring basic principles of physics related to forces, motion, and energy transformations within a defined system.
Transcribed Image Text:**Educational Content on Force and Motion:** **Introduction:** This example explores the dynamics of particles in motion with a given force applied. Specifically, it examines the force exerted by particle 2 on particle 1, represented mathematically by the following equation: \[ \vec{F}_{21}(t) = F_x e^{-(t/T)} \hat{i} + F_y \sin(2\pi t/T) \hat{j} \] where the parameters are specified as: - \( F_x = 16.8 \, \text{N} \) - \( F_y = -106 \, \text{N} \) - \( T = 100 \, \text{s} \) The time interval considered starts at \( t_i = 0 \) and ends at \( t_f = 243 \, \text{s} \). **Key Calculations:** The analysis involves several critical kinetic and dynamic calculations: 1. **Impulse and Force:** - Impulse exerted from particles in both \( x \) and \( y \) directions. - Average force experienced by the particles. 2. **Velocity and Momentum:** - Final velocities of both particles after applying the force over the given interval. - Momentum change in the system. 3. **Energy:** - Changes in kinetic energy for both particles. - Overall change in kinetic energy for the system. **Detailed Calculation Example:** **Displacement of Particle 1 in the \( x \)-direction:** The task was to find the \( x \)-displacement of particle 1, which is calculated to be: \[ \Delta x_1 = 19819.96363 \, \text{m} \] Additional options to find hints or guidance on the problem are available but not specified here. This example provides an illustrative scenario for exploring basic principles of physics related to forces, motion, and energy transformations within a defined system.
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