6) Bob wants to measure the height of a cliff. Unfortunately, he only has with him a stopwatch and a baseball. Luckily, he has a plan. While Jane stays at the bottom of the cliff, Bob climbs up the cliff face. When he reaches the top, he throws the baseball as hard as he can, with a velocity of 33.7m/s at an angle of 22.5°. Some time later, Jane shouts that the ball landed 127 m from the bottom of the cliff.
6) Bob wants to measure the height of a cliff. Unfortunately, he only has with him a stopwatch and a baseball. Luckily, he has a plan. While Jane stays at the bottom of the cliff, Bob climbs up the cliff face. When he reaches the top, he throws the baseball as hard as he can, with a velocity of 33.7m/s at an angle of 22.5°. Some time later, Jane shouts that the ball landed 127 m from the bottom of the cliff.
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### Problem: Measuring the Height of a Cliff
6) Bob wants to measure the height of a cliff. Unfortunately, he only has with him a stopwatch and a baseball. Luckily, he has a plan. While Jane stays at the bottom of the cliff, Bob climbs up the cliff face. When he reaches the top, he throws the baseball as hard as he can, with a velocity of 33.7 m/s at an angle of 22.5°. Some time later, Jane shouts that the ball landed 127 m from the bottom of the cliff.
a) If Bob threw the ball from 1.50 m above the clifftop, how high is the cliff itself?
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This problem involves using physics, specifically kinematics, to determine the height of a cliff based on given parameters of the thrown ball. The setup involves determining the vertical displacement caused by the baseball being thrown from a known height and angle.
#### Explanation:
- **Initial Velocity (v₀)**: 33.7 m/s
- **Angle of Projection (θ)**: 22.5°
- **Horizontal Distance (d)**: 127 m
- **Initial Height of Throw (h₀)**: 1.50 m above the clifftop
##### Steps to Solve:
1. **Resolve the initial velocity into horizontal (v₀x) and vertical (v₀y) components:**
- \( v₀x = v₀ \cdot \cos(\theta) \)
- \( v₀y = v₀ \cdot \sin(\theta) \)
2. **Calculate the time of flight (t) using the horizontal motion:**
- \( d = v₀x \cdot t \)
- \( t = \frac{d}{v₀x} \)
3. **Calculate the vertical displacement (y) using the vertical motion:**
- Equation of motion: \( y = v₀y \cdot t - \frac{1}{2} g t^2 \)
- g (acceleration due to gravity) ≈ 9.8 m/s²
4. **Determine the total height of the cliff:**
- Total height (H) = displacement \(\Delta y\) + initial height (h₀)
By substituting the above-calculated values into their respective equations, the height of
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