The value of effective stress at 4 m depth for the subsoil condition as shown in figure is (Assume Yw = 10 kN/m³) 4 m 1 2 m 2 m 7XXX Capillary saturation upto GL All Sand G, = 2.60 e = 0.60

Q: Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the…

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Q: 'Problem 5. A dense silt layer has the following properties. void ratio = 0.30 eff. Diameter D10 =…

A: Height of capillary riseh=CD10×e

Q: A soil profile consists of sand (9-m thick) which overlies a layer of clay (5-m thick). Ground water…

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Q: A sample was obtained from point A in the submerged clay layer shown below. It was determined that…

A: A )  Given Data : w = 54 % Gs = 2.78  To Find : Effective vertical stress at A ? A problem of Soil…

Q: 1. Calculate total stress, pore-water pressure and effective stress at location A. If the water…

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Q: A consolidated-drained triaxial test on a sand yields the results:All-around confining pressure = σ3…

A: Given; confining pressure = σ3 = 30 lb/in2 axial stress at failure  ; Δσ = 96 lb/in2

Q: 2.5m Im SAND water table SAND Ground Surface Y =16 kN/m³ 3.5 m 7 sez-20 kN/m³ 4.5 m

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Q: Consider a clay layer with a thickness of 36 meters and a Ccɛ = 0.2 and a Crɛ = 0.02.  A circular…

A: Ccɛ = 0.2Crɛ = 0.02D = 20 mqo = 225 kPa

Q: Water flows at the rate of 0.09 ml/s in an upward direction through a sand sample with a coefficient…

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Q: Water flows in the upward direction in a tank through 2.5 m thick sand layer as shown in the figure.…

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Q: The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf…

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Q: Friction angle of dry sand is 330. In a direct shear test on this sand, a normal stress of 100kPa…

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Q: A soil profile consists of sand (6-m thick) which overlies a layer of clay (6-m thick). Ground water…

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Q: A soil particle is found to be subjected to a maximum stress of 14.6 kN/m², and a minimum stress of…

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Q: A soil profile consists of sand (7-m thick) which overlies a layer of clay (9-m thick). Ground water…

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Q: Elevation (m) 2.0 3.0 5.4 20.6 Very fine wet sand with silt w = 5%, S = 40% w = 12%.S = 100% Fine…

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Q: h=1.2 m H1=1 =0.8 Soil H2=2 m valve open In flow

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Q: A uniform surface load of 220 kPa is applied over the area shown below. Estimate the stress increase…

A: The uniform surface load is, To Determine:The stress increase in soil due to surface load at a depth…

Q: The following results were obtained at failure in a series of drained triaxial tests on fully…

A: 38 mm diameter by 76 mm long specimen.    All-round pressure (kN/m2)= 200           400…

Q: Question 1: (10) For the soil profile shown below where H1 = 5 m and H2 = 5 m: a) Calculate the…

A: Solution   in Dry Sandrd = G1+erw = 2.681+0.6x9.81rd = 16.431 kN/m3in ClayrSat = G+e1+e rw =…

Q: Geotech civil engineering

A: Given data : Saturated unit weight (γSat)=18 KN/m3Unit weight of water (γW)=9.8 KN/m3Depth (h)=5 m

Q: topic: geotechnical engineering The ground water level in a thick, very fine sand deposit is…

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Q: Situation 5 (13-15) A 4-m thick sand layer has a void ratio of 0.61 and Gs = 2.65. Underneath the…

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Q: Example 3: A layer of saturated clay 4 m thick is overlain by sand 5 m deep, the water table being 3…

A: The concept of Effective stress was developed by the Terzaghi and it is applied over fully…

Q: The soil profile shown consists of dry sand (5-m thick) which overlies a layer of clay (8-m thick).…

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Q: For the soil profile in the Figure 4 plot the distribution of total and effective vertical stresses…

A: For silt:ρ=1880Kgm3Gs=2.65w=10.5%D10=0.02 mmFor clay:Gs=2.7w=35%

Q: The soil profile shown consists of dry sand (4-m thick) which overlies a layer of clay (3-m thick).…

A: Given data  Sand  Depth of sand = 4m  Void ratio of sand = 0.49  Specific gravity of sand = 2.68…

Q: 5m 3m 2m N.G.L Gs=2.67, e = 0.78 Sand 3 y(sat.) = 18KN/m ³ Silty Clay 20KN Ysat. m3 Gravel

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Q: There is an upward flow of 0.06 ml/s through a sand sample with a coefficient of permeability 3 ×…

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Q: 3. The upward flow of water through a layer of sand in the tank shown in figure has the following…

A: e = 0.50G = 2.67To find:1. Effective stress at point A.2. Effective stress at point B.3. Upward…

Q: 2. Sand at a given relative density has a friction angle of approximately 33° (relatively low…

A: Solution Given data Friction angle ϕ= 330 Pore pressure= 5 KPa unit weight γ= 18 KN/m3

Q: Plot the stress profile for total stress, effective stress and pore water pressure. Show all…

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Q: Derive the following equation using Figure 1 where e is the void ratio, S, is the degree of…

A: Hi there! since you have asked multiple questions, we will solve the first question for you. If you…

Q: 1.5m 0.70 H20 Sand 1.2 e=0.50. 1.0 B valve орen flow

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Q: From the figure shown, H₁ = 0.60, H₂ = 0.90 m. and h = 0.45 m. The sand has a saturated unit weight…

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Q: T I. A ground profile consists of 2 m of silty sand underlain by 3 m of clay. The ground water table…

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Q: .A soil profile is shown in figure below. Dry sand Groundwater table Saturated sand Yu 19.25 KNm 13m…

A: Effective stress = Total stress - Porewater pressure

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.