The total number of bits within a certain fully associative cache is 2056 Kibit. The cache stores 1024 blocks Each block has 64 words and each word is 4 bytos Calculate the size of the tag field and the size of the adtress generated by the processor, in bits. Notice, the address is not necessarily 32-bit Size of the tag field = bits. bits Size of the address = الرجاء إدخال النتيجة بدون مسافة أو وحدة

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A: Below is the answer to above question. I hope this will helpful for you...

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A: For a 4-way set associative cache, the length of the TAG field is given below:

Q: The total number of bits within a certain fuly associative cache is 2056 Kibit. The cache stores…

A: Given cache size= 2056 kbit =257KB Block size=1024×64×4=32KB Then Line offset is:  =cache size /…

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A: Directly Mapped : Index Bits = 4 Offset : 6  Total bits : 32

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Q: chine is X ative cache

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Q: Index Tag Tag (binary) | (8 bits) 1 Valid 00 01 (8 bits) | Valid 10 86 42 69 FD 11 000 AF BC 19 6D 1…

A: The maximum size of met in kb is  =25  =64 kb

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A: Below is the answer to above question. I hope this will be helpful for you....

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Q: address I addres rd size ffer (TI 64 valid

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A: please see the next step for solution

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