The sie of the plysical address space of aprocesor is 2 bytes. Tue word length is2 byles Thc capacity of cache memory is2 bytes The size of cach cache block is2 words Fur a Kway set-associative cachethe length (an number of brts) of themeurytag fields is

Total memory size = physical address space. In k way set associative Cache lines are grouped into…

The se of te phyal dress space o आ नहि procs 2 bytes Te word length is nd lemgth 2 byle The capcity of cache memry is 2 byt e of cach cache block is The s 2woeds For Kwy se cutive cache ury, the lemg n b ber of be) of the g fdein

The se of te phyal dress space o आ नहि procs 2 bytes Te word length is nd lemgth 2 byle The capcity of cache memry is 2 byt e of cach cache block is The s 2woeds For Kwy se cutive cache ury, the lemg n b ber of be) of the g fdein

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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the oneratinn 3) Suppose an application program requires 2500H bytes of memory for its code, 2FOH bytes of memory for its data, and 2A0H bytes of memory for its stack. Shows how this application is positioned in a memory with a 20-bit address bus if locations 00000OH to 0A000H is reserved for the operating system (OS) softtware.
Conflict Based on what we've learned about caches in this class, which of the following situations will cause two blocks to conflict? a) diff tag diff set, diff offset b) diff tag, diff set, same.offset c) diff tag same set, diff offset d) diff tag same set, same offset e) same tag diff set diff offset) f) same tag, diff set, same offset g) same tag, same set, diff offset h) same tag, same set, same offset please I need correct answers in 45 minutes I will give upvote
“Prefetching” is a technique that leverages predictable address patterns to speculatively bring in additional cache blocks when a particular cache block is accessed. One example of prefetching is a stream buff er that prefetches sequentially adjacent cache blocks into a separate buff er when a particular cache block is brought in. If the data is found in the prefetch buff er, it is considered as a hit and moved into the cache and the next cache block is prefetched. Assume a two-entry stream buff er and assume that the cache latency is such that a cache block can be loaded before the computation on the previous cache block is completed. What is the miss rate for the address stream above?Cache block size (B) can aff ect both miss rate and miss latency. Assuming a 1-CPI machine with an average of 1.35 references (both instruction and data) per instruction, help find the optimal block size given the following miss rates for various block sizes. 8: 4% 16: 3% 32: 2% 64: 1.5% 128: 1%…
An associative cache is defined.An associative cache is defined.
s The ain memory of a computer has 2e m ocks while the cache has 2 hocks If the cache uses the set asociative mapping scheme with 2 blocks per set, then block k of the main memory maps to the set
The ability to freely pair data items in a true associative cache is what sets it apart from a directly mapped cache.
How does it function when a cache stores data in a totally associative format?
A CPU l 32b eey ildress nd a 256 K tache menury. The cache is garind as 4y wt ocinive cache wih cache ladk sine of 16 bytes (A) Wht is te aber of seta in the cache? ) What is de sie (in bs) of the ug field per cache black! t) What is the manher and sie of compantors requirad for tag matching (4) How mny sress bis are requirod o find the byte offhet wihin a cache block? (e) What is te tolal a n of extra memeey (in bytes) roquirod for the tag bux?
Oxbe Oxe0 Oxd0 Oxb9 0xe0 Oxc5 Oxdd Ox62 0x73 Oxec Ox6c Oxc9 0x6f Ox94 Ox07 Ox08 Ox3e Oxb2 0x58 0x19 Ox89 0x5c Ox10 0OX88 oxf8 Oxf4 Ox62 0x5f Oxe6 Ox1c Ox66 0xe5 V=1;Tag=0x02; Data = v=1;Tag=0x06; Data = v=1;Tag=0x15; Data = V=0;Tag=0x1a; Data = Ox21 Oxe0 Ox05 0x31 Oxdb Ox30 0x3f 0x81 oxf9 Oxa1 Ox56 0x05 Ox84 Ox68 0xf9 0x78 Oxbd Oxa9 Ox8c Oxc2 oxba Oxe5 Oxe8 Oxac V=1;Tag=0x01; Data = v=1;Tag=0x10; Data = v=1;Tag=0x1d; Data = v=1;Tag=0x0d; Data = 10: Oxba Ox69 0x2c Ox28 Ox64 Oxe4 Ox36 Ox24 ox28 Oxb6 0x2b Ox93 Oxd9 Ox5c Oxb6 0x31 Oxbe Oxd1 Oxfe Ox23 0x13 0x37 0xbb Ox49 ox88 Ox76 Oxee 0x2f Oxao Oxa1 0x1b Ox78 V=1;Tag=0x05; Data = v=1;Tag=0x0f; Data = V=1;Tag=0x13; Data = V=0;Tag=0x1b; Data = Oxob Ox53 Ox26 0xdd Ox3d Oxe9 Ox3f 0x1f Ox02 Ox24 Ox5e Oxef Oxe1 Ox85 Ox33 Oxe3 Ox6e Oxe4 Oxb1 Ox67 Ox6e Oxfb Oxae Ox10 8: !! 9: %3D 11: V=1;Tag=0x1e; Data = v=0;Tag=0x1a; Data = v=1;Tag=0x12; Data = v=1;Tag=0x19; Data = 12: 0x19 0x21 Ox58 Oxfa оx96 Охсе Ох3с Ох23 V=1,Tag=0x1b; Data = V=1;Tag-0x18;…
tn a Gwey number of nesber of cache block ip 256. Neember of blocky Set associative cache worde werds any equal to block sye tag bite cre four size fuhysicel memory
Associative caches and direct-mapped caches are distinct.
c) The table below represents 10 lines from a 256 line cache that uses direct mapping with a block size of 4 words. Identify the address of the shaded data (8C16). 3 Line# Tag Word 10 Word 11 Word Word 00 01 110101 12 34 56 78 1 010101 54 32 6A D3 2 000111 8C A2 BC 29 ED F3 001100 33 20 C8 FO 110011 9A D8