The test statistic in a two-tailed test is z=0.67. Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. Click here to view a partial table of areas under the standard normal curve.
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- An investigation was carried out to study possible consequences of the high incidence of head injuries among soccer players. Three groups of college students (soccer athletes, nonsoccer athletes, and a control group consisting of students who did not participate in intercollegiate sports) were considered in the study. The following table gives information on scores from the Hopkins Verbal Learning Test (which measures immediate memory recall). In addition X = 30.1140. Sample size Sample mean score Sample standard deviation Soccer Athletes 87 30.90 3.93 Nonsoccer Athletes 96 29.94 5.34 Control 52 29.12 3.58 Suppose that it is reasonable to regard these three samples as random samples from the three student populations of interest. Is there sufficient evidence to conclude that the means for Hopkins score are not the same for the three student populations? Use α = 0.05. (Round your answer to two decimal places.) F = Use technology to find the P-value. (Round your answer to four decimal…1.List all of the characteristics of the Standard Normal Distribution. 2.Why is finding the z-score called standardizing data? 3.Does the Empirical Rule apply to the standard normal curve?The average retirement age in America is 63 years old. Do small business owners retire at a different average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 66, 60, 62, 71, 58, 73, 60, 72, 70, 61, 57 What can be concluded at the the a 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: uv = 63 H: uv> c. The test statistic ? = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that O The data suggest the population mean retirement age for small business owners is not significantly different from 63 at a = 0.05, so there is insufficient evidence to conclude that the population mean…
- Big babies: The National Health Statistics Reports described a study in which a sample of 310 one-year-old baby boys were weighed. Their mean weight was 24.4 pounds with standard deviation 5.3 pounds. A pediatrician claims that the mean weight of one-year-old boys is greater than 25 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the α = 0.10 level of significance and the P-value method with the TI-84 Plus calculator. Compute the P-value. Round the answer to at least four decimal places. P-value = ____ How do I solve this problem using the TI-84 calculator?A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 613 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p≠0.5H1: p<0.5B.H0: p=0.5H1: p≠0.5C.H0: p=0.5H1: p<0.5D.H0: p=0.5H1: p>0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Normal distribution Student (t) distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Right-tailed…A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p=0.5H1: p≠0.5B.H0: p=0.5H1: p>0.5C.H0: p=0.5H1: p<0.5D.H0: p≠0.5H1: p=0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? χ2 Normal distribution Student (t) distribution
- purses Researchers conducted an experiment to test the effects of alcohol. Erors were recorded in a test of visual and motor skills for a treatment group of 21 people who drank ethanol and another group of 21 people given a placebo. The errors for the treatment group have a standard deviation of 2.10, and the errors for the placebo group have a standard deviation of 0.71. Use a 0.05 significance level to test the claim that the treatment group has errors that vary significantly more than the errors of the placebo group. Assume that the two populations are normally distributed. se Hom bus What are the null and alternative hypotheses? ndar O A. Ho: o =0 O B. Ho: of +o? ntation OC. Ho o =0 OD. Hoi o? =o} book puncem Identify the test statistic. (Round to two decimal places as needed.) gnments Use technology to identify the P-value. dy Plan (Round to three decimal places as needed.) debook What is the conclusion for this hypothesis test? O A. Reject Ho. There is sufficient evidence to…Americans are about 1 inch taller but nearly 25 pounds heavier than in 1960. The average BMI increased from approximately 25 to 28 in 2002. Boston is considered one of americas healthiest cities. Is the weight gain since 1960 similar in boston? Sample of n=25 and mean increase of 17 with standard deviation of 8.6. Is boston statistically significantly different in terms of weight gain since 1960? Run the appropriate test at 5%level of significance. A.state the null and the research hypotheses, b. Idebtify critical values of z 9r t used to define the decision rule, c. Calculate the test statistic, d. Report the p-value, e. Report your findingsThe commercial for the new Meat Man Barbecue claims that it takes 9 minutes for assembly. A consumer advocate thinks that the assembly time is higher than 9 minutes. The advocate surveyed 14 randomly selected people who purchased the Meat Man Barbecue and found that their average time was 9.7 minutes. The standard deviation for this survey group was 2.2 minutes. What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use z-test for a population proportion v b. The null and alternative hypotheses would be: Ho: H1: c. The test statistic (t 1.191 (please show your answer to 3 decimal places.) d. The p-value = 0.1169 (Please show your answer to 4 decimal places.) e. The p-value is ? ▼ a f. Based on this, we should | Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The data suggest that the population mean amount of time to assemble the Meat Man barbecue is not significantly higher than 9 at a = 0.05,…
- Do shoppers at the mall spend less money on average the day after Thanksgiving compared to the day after Christmas? The 58 randomly surveyed shoppers on the day after Thanksgiving spent an average of $126. Their standard deviation was $35. The 58 randomly surveyed shoppers on the day after Christmas spent an average of $111. Their standard deviation was $32. What can be concluded at the a = 0.01 level of significance? Assuming Equal Variances Tor this study, we shoutd use Select an answer a The null and alternative hypotheses-would be HgSelect an-anower Select an answer v Select an answer v (please enter a decimal) H:Setect an answer v Select an answer V Select an answer v (Please enter a decimal b. The test stattstT is a . The test statistic vatue - (please show your answer to 3 decimal ptaces. d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the conclusion is that ...…The test statistic in a two-tailed test is z= 2.27. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. E Click here to view a partial table of areas under the standard normal curve. The P-value is (Round to four decimal places as needed.)24