A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Ident the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomia distribution. What are the null and alternative hypotheses? OA. Ho: P 0.27 H₁: p<0.27 OC. Ho: p*0.27 H₁: p=0.27 OE. Ho: p*0.27 H₁: p>0.27 What is the test statistic? =-2.21 (Round to two decimal places as needed.) What is the P-value? P-value = 0.0272 (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? OA. Fail to reject the null hypothesis because the P-value is greater than the significance level, c. OB. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OD. Reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? OA. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. OB. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. OC. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. OD. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. B. Ho: p=0.27 H₁: p=0.27 OD. Ho: p=0.27 H₁: p>0.27 OF. Ho: p=0.27 H₁: p<0.27
A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Ident the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomia distribution. What are the null and alternative hypotheses? OA. Ho: P 0.27 H₁: p<0.27 OC. Ho: p*0.27 H₁: p=0.27 OE. Ho: p*0.27 H₁: p>0.27 What is the test statistic? =-2.21 (Round to two decimal places as needed.) What is the P-value? P-value = 0.0272 (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? OA. Fail to reject the null hypothesis because the P-value is greater than the significance level, c. OB. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. OC. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. OD. Reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? OA. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. OB. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. OC. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. OD. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. B. Ho: p=0.27 H₁: p=0.27 OD. Ho: p=0.27 H₁: p>0.27 OF. Ho: p=0.27 H₁: p<0.27
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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Please answer the last two questions please
![A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify
the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial
distribution.
What are the null and alternative hypotheses?
O A.
Ho: p *0.27
H₁: p<0.27
O C. Ho: P 0.27
H₁: p=0.27
O E. Ho: p0.27
H₁: p>0.27
What is the test statistic?
Z= - 2.21
(Round to two decimal places as needed.)
What is the P-value?
P-value = 0.0272
(Round to four decimal places as needed.)
What is the conclusion about the null hypothesis?
O A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.
C. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
O D. Reject the null hypothesis because the P-value is greater than the significance level, a.
What is the final conclusion?
A. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
B. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
C. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
D. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
B. Ho: p=0.27
H₁: p=0.27
D. Ho: p=0.27
H₁: p > 0.27
F. Ho: p = 0.27
H₁: p<0.27](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12f8a0fc-1854-4818-b6ef-1f9785f9b097%2F41b617d8-d767-4151-bc84-9f7fac0af7f7%2Fahz287u_processed.png&w=3840&q=75)
Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify
the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial
distribution.
What are the null and alternative hypotheses?
O A.
Ho: p *0.27
H₁: p<0.27
O C. Ho: P 0.27
H₁: p=0.27
O E. Ho: p0.27
H₁: p>0.27
What is the test statistic?
Z= - 2.21
(Round to two decimal places as needed.)
What is the P-value?
P-value = 0.0272
(Round to four decimal places as needed.)
What is the conclusion about the null hypothesis?
O A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.
C. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
O D. Reject the null hypothesis because the P-value is greater than the significance level, a.
What is the final conclusion?
A. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
B. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
C. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
D. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow.
B. Ho: p=0.27
H₁: p=0.27
D. Ho: p=0.27
H₁: p > 0.27
F. Ho: p = 0.27
H₁: p<0.27
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