The tensile 0.2 percent offset yield strength of AISI 1137 cold-drawn steel bars up to 1 inch in diameter from 2 mills and 25 heats isreported as follows:Sy 9395101f97 99107 109 11119 25 38 17 12 10 5 410310542where Sy is the class midpoint in kpsi and fis the number in each class.Presuming the distribution is normal, determine the yield strength exceeded by 99.0% of the population.The yield strength exceeded by 99.0% of the population iskpsi.

Step 1: Calculate the MeanStep 2:Calculate the Variance and Standard Deviation Step 3: Find the…

Answered: The tensile 0.2 percent offset yield…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Read and Solve carefully please Write clearly and Box the Final answer Express your answer to 3 Significant figures and include appropriate units.
A 1045 hot-rolled steel tension test specimen has the original diameter and length of 6 mm and 25 mm, respectively. The load and change in length data were recorded as shown in Table 1 below: Table 1. Load and change in length Load (KN) Change in Length Load (KN) Change in Length (mm) (mm) 20.56 2.26 2.94 0.01 20.72 3.36 5.58 0.02 20.61 3.83 8.52 0.03 19.97 4.00 11.16 0.04 18.72 Fracture. 12.63 0.05 13.02 0.06 13.16 0.08 13.22 0.10 16.15 0.61 18.50 1.04 20.27 1.80 Page 16 3.1) Calculate stress and strain for the data in Table 1. Please show 1 calculation of stress and 1 of strain. The rest you must tabulate.
A cylindrical steel bar 8 mm in diameter is loaded 1000 cycles per day with a load of 15560 N. How long until fatigue failure takes place? Note: stress = force/area Group of answer choices The bar should not fatigue. The bar will fail in one cycle. 100 days 1000 days
Q1- The engineering tensile stress-strain data were obtained for AA6061-T6 aluminum alloy shown: note stress unit is (MPa). 314 294 266 226 287 325 329 337 334 a.(stress) 0 52 159 E.(strain) 0 1.07 1.70 2.23 3.07 4.80 7.13 9.13 11.33 12.97 14.40 16.10 Plot the stress-strain curves then determine the mechanical properties as followings, ay, ou, elastic zone, plastic zone, Young modulus, fracture stress and ductility if you know L - 30 mm, and Lf - 33.7 mm.
Force P and length change AL data are given in table below for the initial portion of a tension test on 7075-T651 Al alloy. The diameter before testing was 9.07 mm., and the gage length Linitial for t length change measurement was 50.8 mm. What tension force is required to cause yielding in a bar of the same material but with a diameter of 20 mm? P, kN AL mm 7.22 0.0839 14.34 0.1636 21.06 26.8 31.7 34.1 35.0 0.241 0.308 0.380 0.484 0.614 36.0 0.924 36.5 1.279 36.9 37.2 1.622 1.994
A high-impulse universal testing machine is being used to determine the Young's Modulus of a rectangular solid specimen (l = 20 cm, t = 1.5 cm, w = 2 cm). The machine produces 35,000 Ns that causes the impact force of compression resulted to a 1 mm deformation in the length of the specimen in 0.05 s. Determine the Young's modulus of the specimen expressed in MPa. Round off your answer to the nearest whole number
Q-3 The following creep data were taken on an aluminum alloy at 400°C (750°F) and a constant stress of 25 MPa (3660 psi). Plot the data as strain versus time, then determine the steady-state or minimum creep rate. Time Time (min) Strain (min) Strain 0.00 18 0.82 0.22 20 0.88 4 0.34 22 0.95 0.41 24 1.03 8 0.48 26 1.12 10 0.55 28 1.22 12 0.62 30 1.36 14 0.68 32 1.53 16 0.75 34 1.77
1 - A tensile test is carried out on a specimen of mild steel of gauge length 40 mm and diameter 7.42 mm. The results are: Load (kN) 10 17 25 30 34 37.5 38.5 36 Extension (mm) 0 0.05 0.08 0.11 0.14 0.20 0.40 0.60 0.90 At fracture the final length of the specimen is 40.90 mm. Plot the load/ extension graph and determine (a) The modulus of elasticity for mild steel, (b) The yield stress, (c) The ultimate tensile strength, (d) The percentage elongation 2 - An aluminum alloy specimen of gauge length 75 mm and of diameter 11.28 mm was subjected to a tensile test, with these results: Load (kN) 2.0 6.5 11.5 13.6 16.0 18.0 19.0 20.5 19.0 Extension (mm) 0 0.012 0.039 0.069 0.080 0.107 0.133 0.158 0.225 0.310 The specimen fractured at a load of 19.0 kN. Determine (a) the modulus of elasticity of the alloy, (b) The percentage elongation. (c) The ductility in term of reduction of area (d) Fracture stress (e) Tensile strength
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Q1/ The table below shows the values of stress amplitude and life cycles : Fatigue strength Sf (Mpa) Number of cycles (Nf) 474 111 417 496 352 3002 316 7065 290 21930 262 66075 The test were done, to estimate the failure, on un-notched axially load specimens under zero mean stress. Calculate a and b using the stress -life equation.
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