Question 1 Consider the bar, shown in Figure 1, that undergoes axial displacement due to both a distributed load and a point force. The bar is of cross-sectional area A = 1.10-3 m², and has a modulus of elasticity E = 100 GPa. (x) = 5 kN/m 10 kN 4114 X x=0.0 x=2.0 2.0m Figure 1: Bar domain with varying distributed forces. form of the governing ddu(x) dx எ) dx What are the accompanying boundary conditions for this bar? 1 2 1 2 1m 1m Placement, u(x), is given by, Figure 2: Mesh of 2 elements. Elements are numbered with underlines. [6 marks] c) The general form of the element stiffness matrix system, with nodes indexed by i and j, is, AE L 1 {]{}={ * Ni (a) (a) dz } + { N; (2) ƒ (2) – N; (0)ƒ(0) N;(x)l(x)dx N;(2)f(2) - N,(0)f(0)) where f(2) and f(0) denote the boundary forces at positions x = 2 and x Evaluate the right hand side of equation 1 for element 2. = (1) 0, respectively. [18 marks]
Question 1 Consider the bar, shown in Figure 1, that undergoes axial displacement due to both a distributed load and a point force. The bar is of cross-sectional area A = 1.10-3 m², and has a modulus of elasticity E = 100 GPa. (x) = 5 kN/m 10 kN 4114 X x=0.0 x=2.0 2.0m Figure 1: Bar domain with varying distributed forces. form of the governing ddu(x) dx எ) dx What are the accompanying boundary conditions for this bar? 1 2 1 2 1m 1m Placement, u(x), is given by, Figure 2: Mesh of 2 elements. Elements are numbered with underlines. [6 marks] c) The general form of the element stiffness matrix system, with nodes indexed by i and j, is, AE L 1 {]{}={ * Ni (a) (a) dz } + { N; (2) ƒ (2) – N; (0)ƒ(0) N;(x)l(x)dx N;(2)f(2) - N,(0)f(0)) where f(2) and f(0) denote the boundary forces at positions x = 2 and x Evaluate the right hand side of equation 1 for element 2. = (1) 0, respectively. [18 marks]
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...
Question
Answer c
![Question 1
Consider the bar, shown in Figure 1, that undergoes axial displacement due to both a distributed load
and a point force. The bar is of cross-sectional area A = 1.10-3 m², and has a modulus of elasticity
E = 100 GPa.
(x) = 5 kN/m
10 kN
4114
X
x=0.0
x=2.0
2.0m
Figure 1: Bar domain with varying distributed forces.
form of the governing
ddu(x)
dx
எ)
dx
What are the accompanying boundary conditions for this bar?
1
2
1
2
1m
1m
Placement, u(x), is given by,
Figure 2: Mesh of 2 elements. Elements are numbered with underlines.
[6 marks]
c) The general form of the element stiffness matrix system, with nodes indexed by i and j, is,
AE
L
1
{]{}={ * Ni (a) (a) dz } + { N; (2) ƒ (2) – N; (0)ƒ(0)
N;(x)l(x)dx
N;(2)f(2) - N,(0)f(0))
where f(2) and f(0) denote the boundary forces at positions x = 2 and x
Evaluate the right hand side of equation 1 for element 2.
=
(1)
0, respectively.
[18 marks]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60272644-2df7-4793-bdff-d8f1f2c711e5%2F42b8093e-503c-4d38-a17a-bd9b7f114c15%2Fmqco3yn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 1
Consider the bar, shown in Figure 1, that undergoes axial displacement due to both a distributed load
and a point force. The bar is of cross-sectional area A = 1.10-3 m², and has a modulus of elasticity
E = 100 GPa.
(x) = 5 kN/m
10 kN
4114
X
x=0.0
x=2.0
2.0m
Figure 1: Bar domain with varying distributed forces.
form of the governing
ddu(x)
dx
எ)
dx
What are the accompanying boundary conditions for this bar?
1
2
1
2
1m
1m
Placement, u(x), is given by,
Figure 2: Mesh of 2 elements. Elements are numbered with underlines.
[6 marks]
c) The general form of the element stiffness matrix system, with nodes indexed by i and j, is,
AE
L
1
{]{}={ * Ni (a) (a) dz } + { N; (2) ƒ (2) – N; (0)ƒ(0)
N;(x)l(x)dx
N;(2)f(2) - N,(0)f(0))
where f(2) and f(0) denote the boundary forces at positions x = 2 and x
Evaluate the right hand side of equation 1 for element 2.
=
(1)
0, respectively.
[18 marks]
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