The strut is supported by a pin at C and a steel guy wire AB. The wire AB has a diameter of 0.2 in. The maximum normal stress that the steel in the wire can withstand is omax = 18 ksi. Will the wire fail? Show your work and your reasoning.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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### Problem Statement

1. The strut is supported by a pin at C and a steel guy wire AB. The wire AB has a diameter of 0.2 inches. The maximum normal stress that the steel in the wire can withstand is \(\sigma_{\text{max}} = 18 \text{ ksi.}\) Will the wire fail? Show your work and your reasoning.

### Diagram

The diagram illustrates a strut supported at point C and by a guy wire AB. The following details are provided:

- **Wire AB**: Oriented at a \(60^\circ\) angle to the horizontal axis.
- **Force Distribution**: A triangular distributed load of \(200 \text{ lb/ft}\) acts along the horizontal span from point C to point B.
- **Distance CB**: The span length CB is 9 feet.

### Solution Steps

1. **Calculate the Load on the Wire**:
   - Integrate the distributed load over the 9-foot span to find the total load applied horizontally.

2. **Determine the Force in Wire AB**:
   - Use trigonometry to resolve forces, considering the angle of \(60^\circ\).

3. **Calculate the Stress in the Wire**:
   - Use the formula for stress: \(\sigma = \frac{F}{A}\), where \(A\) is the cross-sectional area of the wire.
   - Cross-sectional area, \(A = \pi \left(\frac{0.2}{2}\right)^2\).

4. **Compare with Maximum Allowable Stress**:
   - Determine if the calculated stress exceeds \(\sigma_{\text{max}} = 18 \text{ ksi}\).

This approach will ascertain whether the wire can safely support the load without failure.
Transcribed Image Text:### Problem Statement 1. The strut is supported by a pin at C and a steel guy wire AB. The wire AB has a diameter of 0.2 inches. The maximum normal stress that the steel in the wire can withstand is \(\sigma_{\text{max}} = 18 \text{ ksi.}\) Will the wire fail? Show your work and your reasoning. ### Diagram The diagram illustrates a strut supported at point C and by a guy wire AB. The following details are provided: - **Wire AB**: Oriented at a \(60^\circ\) angle to the horizontal axis. - **Force Distribution**: A triangular distributed load of \(200 \text{ lb/ft}\) acts along the horizontal span from point C to point B. - **Distance CB**: The span length CB is 9 feet. ### Solution Steps 1. **Calculate the Load on the Wire**: - Integrate the distributed load over the 9-foot span to find the total load applied horizontally. 2. **Determine the Force in Wire AB**: - Use trigonometry to resolve forces, considering the angle of \(60^\circ\). 3. **Calculate the Stress in the Wire**: - Use the formula for stress: \(\sigma = \frac{F}{A}\), where \(A\) is the cross-sectional area of the wire. - Cross-sectional area, \(A = \pi \left(\frac{0.2}{2}\right)^2\). 4. **Compare with Maximum Allowable Stress**: - Determine if the calculated stress exceeds \(\sigma_{\text{max}} = 18 \text{ ksi}\). This approach will ascertain whether the wire can safely support the load without failure.
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