The reaction below will form CH H₂O H3C H H2SO4 a) 2 compounds and a meso compound. b) a meso compound. c) a racemic mixture. d) a pair of enantiomers and a meso compound. e) a pair of enantiomers. f) a pair of diastereomers.
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- ? Modify the given carbon skeleton to draw the major product(s). If a racemic mixture of enantiomers is expected, draw both enantiomers. Note: you can select a structure and use Copy and Paste to save drawing time. C A z + : 1) OsO4 2) NaHSO,/ H₂O H3C CH3 H с N O P S LL F CI Br I ishow the stereochemistryWhat type of product t is formed from this reaction? A meso compound, a racemic mixture or a single enantiomer?
- What product(s) is(are) formed in the following reaction Br/CH-Clz Br plus enantiomer H3C Et Br Br H and H3C Br H3C Et Et Br он ...Et plus enantiomer H3C BrFill in the missing reactant along with optically active or racemic name and what reaction it goes by E1, E2, SN1, OR SN2Predict the major product of this series of reactions. The squiggly bond simply indicates the stereochemistry is unknown, i.e., wedge or dash. HBr compound I 1. NaH 2. compoundI 3. H2, Lindlar 4. Br2, H20 OH Br А. Br C. OH OH Br Br В. D. OH A.
- Draw the substitution mechanisim that would take place[Review Topics] [References] Classify the following compounds as chiral, achiral (but not meso), or meso. H OH 1st structure: HO chiral OH achiral 2nd structure: meso OH 3rd structure: CIFor the following reaction, decide whether a solution of the products would be optically active or not and why. You will need to know the product of this reaction in order to solve this problem. To preview the image click here Br CH3 Na: CEN: acetone O Not optically active, achiral product is formed O Not optically active, racemic mixture is formed O Not optically active, a meso compound is formed O Optically active, a single enantiomer is formed
- s sugar X a reducing or a non-reducing sugar? Reducing, because one/both of the rings can open to expose a free aldehyde group Non-reducing, because one/both of the rings can open to expose a free aldehyde group Reducing, because neither of the rings can open to expose a free aldehyde group Non-reducing, because neither of the rings can open to expose a free aldehyde group Reducing, because one/both of the rings can open to expose a free ketone group Non-reducing, because one/both of the rings can open to expose a free ketone group Reducing, because neither of the rings can open to expose a free ketone group Non-reducing, because neither of the rings can open to expose a free ketone group Cannot be determined from the structure shownH2 H H Pt/C Product is (circle one) i. A racemic mixture ii. A single enantiomer, iii. Achiral or mesoDraw the meso form of this compound. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Show stereochemistry in a meso compound.