The reaction below will form CH H₂O H3C H H2SO4 a) 2 compounds and a meso compound. b) a meso compound. c) a racemic mixture. d) a pair of enantiomers and a meso compound. e) a pair of enantiomers. f) a pair of diastereomers.
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- :$;$;$;$$:$$:$;$? Modify the given carbon skeleton to draw the major product(s). If a racemic mixture of enantiomers is expected, draw both enantiomers. Note: you can select a structure and use Copy and Paste to save drawing time. C A z + : 1) OsO4 2) NaHSO,/ H₂O H3C CH3 H с N O P S LL F CI Br I iWhat type of product t is formed from this reaction? A meso compound, a racemic mixture or a single enantiomer?
- 8. Identify the stereochemical relationship between the structural pairs shown below as (A) identical structures that are not meso; (B) identical structures that ARE meso; (C) structures that are enantiomers; or (D) structures that are diastereomers. a) b) H3C c) CH3 Br H. CH3 Br Br CH3 H. CI Holl H Cill Cl- CH3 Br H. CI CH3 HO. H. H3C Cl H3C- H- H. CH3 Cl a) b) c) 9. Identify the stereochemical relationship between the structural pairs shown below as (A) identical structures that are not meso; (B) identical structures that ARE meso; (C) structures that are enantiomers; or (D) structures that are diastereomers. a) b) c) CH2CH3 NH2 HO CH3 H3C. CH3 Cl HO H;C CH2CH3 F. F H;C. CI H H,N -CH3 CH3 NH2 H3C Br H2N C1 H3C CH3 CH3 H;CH,C- Cl F H. H Br CH,CH3 CH3 a) b) c)see these instructions. Consider stereochemistry and enter either enantiomer (but not both) if a racemic mixture of products forms. If a mixture of two diastereomers is expected, enter either (but not both). 1. MgCl 2. H₂O:):)):;););)/(/);$:$
- × Your answer is incorrect. 1) RCO₂H ? 2) [H2SO4], OH Modify the given structure to draw the major product(s). Use the single bond tool to interconvert between double and single bonds. If a racemic mixture of enantiomers is expected, draw both enantiomers. Note: you can select a structure and use Copy and Paste to save drawing time. H3C H3C CH3 CH3 OH H3C CH3 O OH HO CH3 Edit Drawing CH3 SUPPOR08.20b 1) ВН, THF 2) H,O2, NaOH Modify the given carbon skeleton to draw the major product(s) of the given reaction. If a racemic mixture of enantiomers is expected, draw both enantiomers. Note: you can select a structure and use Copy and Paste to save drawing time. CHa) Draw both chair conformations of the starting alkyl bromide. Indicate which conformation, if either is more stable. Briefly justify your answer. b) The starting alkyl halide has two chiral carbons. What are the configurations (R/S) at each of these carbons? c) Identify the mechanism (E1/E2) which reactions 1, 2, and 3 proceed by. d) Provide mechanisms that explain the products formed in reactions 1, 2, and 3. All electron movement must be shown in order to receive full credit. e) Indicate which product is the major and which product is the minor in reactions 2 and 3. Briefly justify your answer.
- a) Draw both chair conformations of the starting alkyl bromide. Indicate which conformation, if either is more stable. Briefly justify your answer. b) The starting alkyl halide has two chiral carbons. What are the configurations (R/S) at each of these carbons? c) Identify the mechanism (E1/E2) which reactions 1, 2, and 3 proceed by. d) Provide mechanisms that explain the products formed in reactions 1, 2, and 3. All electron movement must be shown in order to receive full credit. e) Indicate which product is the major and which product is the minor in reactions 2 and 3. Briefly justify your answer.a) Draw both chair conformations of the starting alkyl bromide. Indicate which conformation, if either is more stable. Briefly justify your answer. b) The starting alkyl halide has two chiral carbons. What are the configurations (R/S) at each of these carbons? c) Identify the mechanism (E1/E2) which reactions 1, 2, and 3 proceed by. d) Provide mechanisms that explain the products formed in reactions 1, 2, and 3. All electron movement must be shown in order to receive full credit. e) Indicate which product is the major and which product is the minor in reactions 2 and 3. Briefly justify your answer.For the following reaction, decide whether a solution of the products would be optically active or not and why. You will need to know the product of this reaction in order to solve this problem. To preview the image click here Br CH3 Na: CEN: acetone O Not optically active, achiral product is formed O Not optically active, racemic mixture is formed O Not optically active, a meso compound is formed O Optically active, a single enantiomer is formed