Are blonde female college students less likely to have boyfriends than brunette female college students? 418 of the 669 blondes surveyed had boyfriends and 453 of the 660 brunettes surveyed had boyfriends. What can be concluded at the αα = 0.05 level of significance?For this study, we should use The null and alternative hypotheses would be: H0:H0: (please enter a decimal) H1:H1: (Please enter a decimal)The test statistic = (please show your answer to 3 decimal places.)The p-value = (Please show your answer to 4 decimal places.)The p-value is ααBased on this, we should the null hypothesis.Thus, the final conclusion is that ...The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of blonde college students who have a boyfriend is less than the population proportion of brunette college students who have a boyfriend.The results are statistically insignificant at αα = 0.05, so there is insufficient evidence to conclude that the population proportion of blonde college students who have a boyfriend is less than the population proportion of brunette college students who have a boyfriend.The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the proportion of the 669 blonde college students who have a boyfriend is less than the proportion of the 660 brunette college students who have a boyfriend.The results are statistically insignificant at αα = 0.05, so we can conclude that the population proportion of blonde college students who have a boyfriend is equal to the population proportion of brunette college students who have a boyfriend.Interpret the p-value in the context of the study.If the percent of all blonde college students who have a boyfriend is the same as the percent of all brunette college students who have a boyfriend and if another 669 blonde college students and 660 brunette college students are surveyed then there would be a 0.91% chance that the percent of the surveyed blonde college students who have a boyfriend would be at least 6.2% less than the percent of the surveyed brunette college students who have a boyfriend.There is a 0.91% chance of a Type I error.If the sample proportion of blonde college students who have a boyfriend is the same as the sample proportion of brunette college students who have a boyfriend and if another another 669 blonde college students and 660 brunette college students are surveyed then there would be a 0.91% chance of concluding that blonde college students are at least 6.2% less likely than brunette college students to have a boyfriendThere is a 0.91% chance that blonde college students are 6.2% less likely than brunette college students to have a boyfriend.Interpret the level of significance in the context of the study.If the percent of all blonde college students who have a boyfriend is the same as the percent of all brunette college students who have a boyfriend and if another 669 blonde college students and 660 brunette college students are surveyed then there would be a 5% chance that we would end up falsely concuding that the population proportion of blonde college students who have a boyfriend is less than the population proportion of brunette college students who have a boyfriendIf the percent of all blonde college students who have a boyfriend is the same as the percent of all brunette college students who have a boyfriend and if another 669 blonde college students and 660 brunette college students are surveyed then there would be a 5% chance that we would end up falsely concuding that the proportion of these surveyed blonde and brunette college students who have a boyfriend differ from each other.There is a 5% chance that there is a difference in the proportion of blonde and brunette college students who have a boyfriend.There is a 5% chance that you will never get a boyfriend unless you dye your hair blonde.

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Answered: The null and alternative hypotheses…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Are blonde female college students less likely to have boyfriends than brunette female college students? 418 of the 669 blondes surveyed had boyfriends and 453 of the 660 brunettes surveyed had boyfriends. What can be concluded at the αα = 0.05 level of significance?

For this study, we should use

The null and alternative hypotheses would be:

H0:H0: (please enter a decimal)

H1:H1: (Please enter a decimal)

The test statistic = (please show your answer to 3 decimal places.)
The p-value = (Please show your answer to 4 decimal places.)
The p-value is αα
Based on this, we should the null hypothesis.
Thus, the final conclusion is that ...
- The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of blonde college students who have a boyfriend is less than the population proportion of brunette college students who have a boyfriend.
- The results are statistically insignificant at αα = 0.05, so there is insufficient evidence to conclude that the population proportion of blonde college students who have a boyfriend is less than the population proportion of brunette college students who have a boyfriend.
- The results are statistically significant at αα = 0.05, so there is sufficient evidence to conclude that the proportion of the 669 blonde college students who have a boyfriend is less than the proportion of the 660 brunette college students who have a boyfriend.
- The results are statistically insignificant at αα = 0.05, so we can conclude that the population proportion of blonde college students who have a boyfriend is equal to the population proportion of brunette college students who have a boyfriend.
Interpret the p-value in the context of the study.
- If the percent of all blonde college students who have a boyfriend is the same as the percent of all brunette college students who have a boyfriend and if another 669 blonde college students and 660 brunette college students are surveyed then there would be a 0.91% chance that the percent of the surveyed blonde college students who have a boyfriend would be at least 6.2% less than the percent of the surveyed brunette college students who have a boyfriend.
- There is a 0.91% chance of a Type I error.
- If the sample proportion of blonde college students who have a boyfriend is the same as the sample proportion of brunette college students who have a boyfriend and if another another 669 blonde college students and 660 brunette college students are surveyed then there would be a 0.91% chance of concluding that blonde college students are at least 6.2% less likely than brunette college students to have a boyfriend
- There is a 0.91% chance that blonde college students are 6.2% less likely than brunette college students to have a boyfriend.
Interpret the level of significance in the context of the study.
- If the percent of all blonde college students who have a boyfriend is the same as the percent of all brunette college students who have a boyfriend and if another 669 blonde college students and 660 brunette college students are surveyed then there would be a 5% chance that we would end up falsely concuding that the population proportion of blonde college students who have a boyfriend is less than the population proportion of brunette college students who have a boyfriend
- If the percent of all blonde college students who have a boyfriend is the same as the percent of all brunette college students who have a boyfriend and if another 669 blonde college students and 660 brunette college students are surveyed then there would be a 5% chance that we would end up falsely concuding that the proportion of these surveyed blonde and brunette college students who have a boyfriend differ from each other.
- There is a 5% chance that there is a difference in the proportion of blonde and brunette college students who have a boyfriend.
- There is a 5% chance that you will never get a boyfriend unless you dye your hair blonde.

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The null and alternative hypotheses would be: H0:H0: (please enter a decimal) H1:H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα