Assume that IQ scores for a certain population are approximately N (µ, o² = 100). To test Ho : µ = 110 against the one-tailed alternative hypothesis Ha : µ > 110, we take a random sample of size n = 16 from this population and observe ī = 113.5. Do we accept or reject Ho at the 5% significance level? Do we accept or reject Ho at the 10% significance level? )What is the p-value of this test?

Assume that IQ scores for a certain population are approximately N (µ, o² = 100). To test Ho : µ = 110 against the one-tailed alternative hypothesis Ha : µ > 110, we take a random sample of size n = 16 from this population and observe ī = 113.5. Do we accept or reject Ho at the 5% significance level? Do we accept or reject Ho at the 10% significance level? )What is the p-value of this test?

Name: Assume that IQ scores for a certain population are approximately N (µ
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Assume that IQ scores for a certain population are approximately N (µ, o? = 100). Totest Ho : µ = 110 against the one-tailed alternative hypothesis Ha : µ > 110, we take arandom sample of size n = 16 from this population and observe ī = 113.5.Do we

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

You wish to test the following claim (Ha) at a significance level of a = 0.002. = Ho: P₁ Ha: P1 P2 P2 You obtain a sample from the first population with 594 successes and 78 failures. You obtain a sample from the second population with 558 successes and 44 failures. The test statistic is... O in the critical region not in the critical region critical value = test statistic = This test statistic leads to a decision to... reject the null hypothesis fail to reject the null hypothesis [three decimal accuracy] [three decimal accuracy] As such, the final conclusion is that... O There is sufficient evidence to support that the first population proportion is less than the second population proportion. There is not sufficient evidence to support that the first population proportion is less than the second population proportion.
The recidivism rate for convicted sex offenders is 13%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 309 convicted sex offenders who were also drug addicts, 31 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Ho: ? ✓ Select an answer H₁: ? Select an answer (please enter a decimal) (Please enter a decimal) The test statistic ? ✓ = The p-value = The p-value is ? va Based on this, we should [Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the population proportion is not significantly different from 13% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…
You wish to test the claim that the average IQ score is less than 100 at the .10 significance level. You determine the hypotheses are: Ho: μ=100Ho: μ=100 H1:μ<100H1:μ<100 You take a simple random sample of 73 individuals and find the mean IQ score is 95.2, with a standard deviation of 15.1. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ…
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.85. You use a significance level of α=0.002α=0.002. H0:p=0.85H0:p=0.85 H1:p≠0.85H1:p≠0.85You obtain a sample of size n=415n=415 in which there are 361 successes.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 25 g equals about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis, Ho: u = 2.08, against the alternative hypothesis, H1: µ # 2.08, where u is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. Sample size Sample mean Sample standard deviation Test statistic Probability value P-value 45 2.04 0.14 -2.076 0.044 Based on these results, complete the following sentences to state the decision and conclusion of the test.…
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.34. You use a significance level of α=0.005α=0.005. H0:p=0.34H0:p=0.34 H1:p≠0.34H1:p≠0.34You obtain a sample of size n=551n=551 in which there are 164 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =
Only 12% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 390 randomly selected registered voters surveyed, 62 of them will vote in the upcoming election. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > < ≠ = (please enter a decimal) H1:H1: ? p μ Select an answer ≠ < = > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly higher than 12% at αα = 0.01, so…
A test of Ho: H=0 versus H₁: >0 is performed using a significance level of a=0.05. The P-value is 0.07. Part: 0/3 Part 1 of 3 (a) Is Ho rejected? Since P Part: 1/3 Part 2 of 3 Part: 2/3 ▾a, we do not reject Ho at the a= 0.05 level. (b) If the true value of μ is 0, is the result a Type I error, a Type II error, or a correct decision? The result is a correct decision Part 3 of 3 X X S (c) If the true value of His 4, is the result a Type I error, a Type II error, or a correct decision? S Español
You wish to test the following claim (Ha) at a significance level of a = Ho: P₁ = P2 Ha: P₁ P2 You obtain a sample from the first population with 120 successes and 403 failures. You obtain a sample from the second population with 39 successes and 278 failures. The test statistic is... in the critical region O not in the critical region critical value = ± test statistic = This test statistic leads to a decision to... reject the null hypothesis fail to reject the null hypothesis = 0.005. O There is not sufficient evidence to support second population proportion. [three decimal accuracy] [three decimal accuracy] As such, the final conclusion is that... There is sufficient evidence to support that the first population proportion is not equal to the second population proportion. first population proportion not equal to the
Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…
You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.27. You use a significance level of α=0.001. H0:p=0.27H0:p=0.27 H1:p≠0.27H1:p≠0.27You obtain a sample of size n=406n=406 in which there are 97 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the probability of a true negative on a test for a certain cancer is different from 0.27. There is not sufficient evidence to warrant rejection of the claim that the probability of a true negative on a test for a…