about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis, Họ:µ = 2.08, against the alternative hypothesis, H1:µ # 2.08, where u is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics fo her test are shown in the following table. Sample size Sample mean Sample standard deviation Test statistic Probability value n P-value 45 2.04 0.14 -2.076 0.044 Based on these results, complete the following sentences to state the decision and conclusion of the test.

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Suppose the nutrition information on the package of Matilde’s favorite brand of chips states that a serving size of 25 g equals about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample *t*-test with a significance level of α = 0.10 to test the null hypothesis, H₀: μ = 2.08, against the alternative hypothesis, H₁: μ ≠ 2.08, where μ is the average weight of a chip.

Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table.

| Sample size | Sample mean | Sample standard deviation | Test statistic | Probability value |
|-------------|-------------|---------------------------|----------------|-------------------|
| n           | x̄          | s                         | t              | P-value           |
| 45          | 2.04        | 0.14                      | -2.076         | 0.044             |

Based on these results, complete the following sentences to state the decision and conclusion of the test.

Matilde's decision is to **reject** the **null hypothesis** (P = 0.044). There is **sufficient** evidence to **disprove** the claim that the average weight of **the sample of chips** is **equal to** **2.08 g**.

**Answer Bank:**

- the sample of chips
- greater than
- different than
- all chips of this brand
- no
- some
- 2.08 g
- equal to
- null hypothesis
- reject
- alternative hypothesis
- support
- fail to reject
- 0.044
- disprove
- 2.04 g
- prove
- sufficient
- accept
- 10%
- less than
- 45
- fail to accept
- 0.10
- 0.14 g
- -2.076
- one-sample t-test
- sample proportion
- insufficient
Transcribed Image Text:Suppose the nutrition information on the package of Matilde’s favorite brand of chips states that a serving size of 25 g equals about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample *t*-test with a significance level of α = 0.10 to test the null hypothesis, H₀: μ = 2.08, against the alternative hypothesis, H₁: μ ≠ 2.08, where μ is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. | Sample size | Sample mean | Sample standard deviation | Test statistic | Probability value | |-------------|-------------|---------------------------|----------------|-------------------| | n | x̄ | s | t | P-value | | 45 | 2.04 | 0.14 | -2.076 | 0.044 | Based on these results, complete the following sentences to state the decision and conclusion of the test. Matilde's decision is to **reject** the **null hypothesis** (P = 0.044). There is **sufficient** evidence to **disprove** the claim that the average weight of **the sample of chips** is **equal to** **2.08 g**. **Answer Bank:** - the sample of chips - greater than - different than - all chips of this brand - no - some - 2.08 g - equal to - null hypothesis - reject - alternative hypothesis - support - fail to reject - 0.044 - disprove - 2.04 g - prove - sufficient - accept - 10% - less than - 45 - fail to accept - 0.10 - 0.14 g - -2.076 - one-sample t-test - sample proportion - insufficient
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