20% of all college students volunteer their time. Is the percentage of college students who are volunteersdifferent for students receiving financial aid? Of the 352 randomly selected students who receive financialaid, 49 of them volunteered their time. What can be concluded at the a 0.01 level of significance?a. For this study, we should use z-test for a population proportion Vb. The null and alternative hypotheses would be:Ho:Select an answer(please enter a decimal)Select an answer V(Please enter a decimal)C. The test statistic(please show your answer to 3 decimal places.)d. The p-value =(Please show your answer to 4 decimal places.)e. The p-value is ? vf. Based on this, we should Select an answer v the null hypothesis.g. Thus, the final conclusion is thatThe data suggest the populaton proportion is significantly different from 20% at a = 0.01, sothere is sufficient evidence to conclude that the percentage of financial aid recipients whovolunteer is different from 20%.The data suggest the population proportion is not significantly different from 20% at a = 0.01,so there is sufficient evidence to conclude that the percentage of financial aid rcipients whovolunteer is equal to 20%.O The data suggest the population proportion is not significantly different from 20% at a = 0.01,so there is insufficient evidence to conclude that the percentage of financial aid recipientswho volunteer is different from 20%

We want to find null hypothesis, alternate hypothesis and test statistics Note: According to…

Answered: 20% of all college students volunteer…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- E
Suppose that at a particular college, a random sample found that 25 out of 100 students who use the internet use Twitter. Does this provide evidence that the true proportion of students at this college who use Twitter is higher than the nationally stated 15%? Use a significance level of 0.05 and the p-value to give your decision. The correct hypotheses to use are: Ho: p = 0.15 HA: p > 0.15 Blank #1: Report the test statistic to two decimal places Blank #2: Report the p-value to four decimal places. Blank #3: Give the test decision: (reject or do not reject) Ho Blank #4: Evidence _[favors or does not favor) that the true proportion of students at this college who use Twitter is higher than the nationally stated 15%.
Perform the following hypothesis test of a proportion: HO: p = 0.125 HA: p 0.125 The sample proportion is 0.1 based on a sample size of 95. Use a 10% significance level. The critical values of the test statistic that divide the rejection and non-rejection regions are what value?
A business owner claims that the proportion of take out orders is greater than 25%. To test this claim, the owner checks the next 250 orders and determines that 60 orders are take out orders The following is the setup for this hypothesis test: Ho :p 0.25 Ha p>0.25 In this example, the p-value was determined to be 0.643. come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%) Select the correct answer below: O The decision is to reject the Null Hypothesis. The conclusion is that there is enough evidence to support the claim. The decision is to fail to reject the Null Hypothesis. The conclusion is that there is not enough evidence to support the claim.
Find test value and p-score.
Test the claim that the proportion of men who own cats is significantly different than 20% at the 0.02 significance level. The null and alternative hypothesis would be: Ho:µ = 0.2 Ho:H = 0.2 Ho:p= 0.2 Ho:µ = 0.2 Ho:p= 0.2 Ho:p= 0.2 H1: µ > 0.2 H1:470.2 H1:p7 0.2 H1:µ 0.2 The test is: left-tailed right-tailed two-tailed Based on a sample of 4 people, 25% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis Check Answer
Perform the following hypothesis test of a proportion: HO: p = 0.125 HA: p 0.125 The sample proportion is 0.1 based on a sample size of 95. Use a 10% significance level. What is the p-value?
The national percentage of automobile accident fatalities that are alcohol related is 39%. In a random sample of 96 automobile accident fatalities in the state of New York, 44 were alcohol related. Is this sufficient evidence to say that new York has a higher percentage of alcohol related automobile fatalities? a. Perform the appropriate test of hypothesis and paste the session window output below. b. What is the value of the test statistic? c. At a = .10, what is your decision?
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
please answer d, e, f f; accept, reject, fail to reject
A researcher wants to know if there is a statistically significant difference between Liberal Arts majors and other students on average number of books (other than those required by course work) read per year. To test this research question, sample students attending a large university have been randomly selected. Using the sample information suggested below, conduct a hypothesis test at 0.05 significance level. Sample 1 (Liberal Arts majors) Sample 2 (Other majors) = 16.2 = 13.7 s1 = 2.3 s2 = 9.0 N1 = 236 N2 = 321 - What is the critical Z-score? - Compute the test statistic value (i.e., calculated or obtained Z-score). -Determine if the null hypothesis is rejected AND state what it means.
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