b. What is the test statistic?c. What is the P-value?d. Identify the null hypothesisDecide whether to reject the null hypothesis. Refer to image for letter e. Hope someone can help, thanks! e. What is the final conclusion?O A. There is not sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches.O B. There is sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches.OC. There is not sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches.O D. There is sufficient evidence to warrant rejection of the claim that less than 9% of treated subjects experienced headaches. A certain drug is used to treat asthma. In a clinical trial of the drug, 30 of 282 treated subjects experienced headaches (based on data fromthe manufacturer). The accompanying calculator display shows results from a test of the claim that less than 10% of treated subjectsexperienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.01 significance levelto complete parts (a) through (e) below.1-PropZTestprop <0.1z = 0.357294801p = 0.6395644392p= 0.1063829787n= 282a. Is the test two-tailed, left-tailed, or right-tailed?O Two-tailed testO Right tailed testLeft-tailed test

From the provided information, Population proportion (p) = 0.10 The hypotheses can be constructed as: H0: p = 0.10 H1: p < 0.10 a) The test is left tailed. Level of significance (α) = 0.01 Sample size (n) = 282 Out of which 30 experienced headaches that is x = 30 The sample proportion can be obtained as:b) The value of the test statistic can be obtained as:c) The p value of the test statistic from the standard normal table is 0.3602. d) Since, the p value is greater than level of significance, therefore, the null hypothesis would fail to reject. e) There is not sufficient evidence to support the claim that less than 10% of treated subjects experienced headaches.