A genetic experiment involving peas yielded one sample of offspring consisting of 411 green peas and 137 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 23% of offspring peas willbe yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distributionas an approximation to the binomial distribution.What are the null and alternative hypotheses?O A. Ho: p#0.23О В. Но: р- 0.23H1: p>0.23H1: p< 0.23ОС. Но: р30.23O D. Ho: p= 0.23H1: p+0.23H1: p>0.23O E. Ho: p#0.23H1: p=0.23O F. Ho: p#0.23H1:p< 0.23What is the test statistic?z=(Round to two decimal places as needed.)What is the P-value?P-value = What is the conclusion about the null hypothesis?O A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.O B. Reject the null hypothesis because the P-value is greater than the significance level, a.OC. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.O D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.What is the final conclusion?O A. There is sufficient evidence to support the claim that less than 23% of offspring peas will be yellow.O B. There is not sufficient evidence to support the claim that less than 23% of offspring peas will be yellow.O C. There is not sufficient evidence to warrant rejection of the claim that 23% of offspring peas will be yellow.O D. There is sufficient evidence to warrant rejection of the claim that 23% of offspring peas will be yellow.

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A genetic experiment involving peas yielded one sample of offspring consisting of 411 green peas and 137 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.23 ОВ. Но: р 0.23 H1: p>0.23 H1: p<0.23 ОС. Но: р30.23 O D. Họ: p = 0.23 H: p>0.23 H: p=0.23 O E. Ho: p#0.23 OF. Ho: p=0.23 Hị: p= 0.23 Hz:p<0.23 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value =

A genetic experiment involving peas yielded one sample of offspring consisting of 411 green peas and 137 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.23 ОВ. Но: р 0.23 H1: p>0.23 H1: p<0.23 ОС. Но: р30.23 O D. Họ: p = 0.23 H: p>0.23 H: p=0.23 O E. Ho: p#0.23 OF. Ho: p=0.23 Hị: p= 0.23 Hz:p<0.23 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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