The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y= 2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length of the bar, and E= 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length of the bar (c) the maximum normal strain in the bar. Answer: (a) ō = i (b) &ave ics = i x10.6 in. με US
The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y= 2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length of the bar, and E= 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length of the bar (c) the maximum normal strain in the bar. Answer: (a) ō = i (b) &ave ics = i x10.6 in. με US
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E wherey=
2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length
of the bar, and E = 23000 ksi is a material constant. Determine,
(a) the change in length of the bar due to its own weight.
(b) the average normal strain over the length of the bar
(c) the maximum normal strain in the bar.
Answer:
(a) ō = i
(b) Eave
= i
(c) Emax =
i
x10-in.
με
με
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