The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y= 2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length of the bar, and E= 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length of the bar (c) the maximum normal strain in the bar. Answer: (a) ō = i (b) &ave ics = i x10.6 in. με US

The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y= 2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length of the bar, and E= 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length of the bar (c) the maximum normal strain in the bar. Answer: (a) ō = i (b) &ave ics = i x10.6 in. με US

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Strain energy

The term strain indicates the variation in an object's length, area, and volume when the object is subjected to an external force. The external force may be of normal, shear, moment, torque, etc. The strain in an object depends on the types of external force and cross-section of the object. Mathematically, the evaluation of strain can be obtained with the help of elastic constants.

Question

The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E wherey=
2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length
of the bar, and E = 23000 ksi is a material constant. Determine,
(a) the change in length of the bar due to its own weight.
(b) the average normal strain over the length of the bar
(c) the maximum normal strain in the bar.
Answer:
(a) ō = i
(b) Eave
= i
(c) Emax =
i
x10-in.
με
με

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