The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y=2.4 lb/in.³ is the specific weight of the material, y = 0.6 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the length of the bar, and E=30000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 5-1 (b) = 1 (c) max= x10 in. HE με

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where
y=2.4 lb/in.³ is the specific weight of the material, y = 0.6 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the
length of the bar, and E=30000 ksi is a material constant. Determine,
(a) the change in length of the bar due to its own weight.
(b) the average normal strain over the length L of the bar
(c) the maximum normal strain in the bar.
Answer:
(a) 5 = 1
(b) Sa
(c) Emax=
i
x10-6 in.
με
με
Transcribed Image Text:The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y=2.4 lb/in.³ is the specific weight of the material, y = 0.6 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the length of the bar, and E=30000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 5 = 1 (b) Sa (c) Emax= i x10-6 in. με με
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