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The cross-sectional area of the figure below is 0.5 in2. If E = 13 x 106 psi, calculate the total length deformation. (positive deformation mean the material elongates and negative deformation mean the material shortens) P1 P2– P3 P4 a b P1 = 4,400 lb a = 4 in P2 = 7,700 Ib b = 8 in P3 = 8,000 lb C = 4 in P4 = P1 - P2 + P3 %3D

The cross-sectional area of the figure below is 0.5 in2. If E = 13 x 106 psi, calculate the total length deformation. (positive deformation mean the material elongates and negative deformation mean the material shortens) P1 P2– P3 P4 a b P1 = 4,400 lb a = 4 in P2 = 7,700 Ib b = 8 in P3 = 8,000 lb C = 4 in P4 = P1 - P2 + P3 %3D

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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The cross-sectional area of the figure below is 0.5 in2. If E = 13 x 106 psi, calculate the total length deformation. (positive deformation mean the material elongates and negative deformation mean the material shortens) P1- P2 P3 P4 a b P1 = 4,400 lb a = 4 in P2 = 7,700 lb b = 8 in P3 = 8,000 lb C = 4 in P4 = P1 - P2 + P3
Transcribed Image Text:The cross-sectional area of the figure below is 0.5 in2. If E = 13 x 106 psi, calculate the total length deformation. (positive deformation mean the material elongates and negative deformation mean the material shortens) P1- P2 P3 P4 a b P1 = 4,400 lb a = 4 in P2 = 7,700 lb b = 8 in P3 = 8,000 lb C = 4 in P4 = P1 - P2 + P3
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