The motor in a toy car operates on 6.00 V, developing a 4.70 V back emf at normal speed. If it draws 3.00 A at normal speed, what current (in A) does it draw when starting? ____________ A
The motor in a toy car operates on 6.00 V, developing a 4.70 V back emf at normal speed. If it draws 3.00 A at normal speed, what current (in A) does it draw when starting? ____________ A
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The motor in a toy car operates on 6.00 V, developing a 4.70 V back emf at normal speed. If it draws 3.00 A at normal speed, what current (in A) does it draw when starting?
____________ A
![**Problem Statement:**
The motor in a toy car operates on 6.00 V, developing a 4.70 V back emf at normal speed. If it draws 3.00 A at normal speed, what current (in A) does it draw when starting?
**Solution Approach:**
- Calculate the resistance (R) using Ohm's Law at normal speed.
- Use the resistance to find the starting current, assuming no back emf at start.
**Given Data:**
- Operating voltage (V) = 6.00 V
- Back electromotive force (emf) at normal speed = 4.70 V
- Current at normal speed = 3.00 A
- Voltage across the motor at normal speed = V - Back emf
**Calculation Steps:**
1. Calculate resistance (R) at normal speed:
\[
R = \frac{V_{\text{effective}}}{I} = \frac{6.00 \text{ V} - 4.70 \text{ V}}{3.00 \text{ A}}
\]
2. Calculate starting current (I) with V = 6.00 V and no back emf:
\[
I = \frac{V}{R}
\]
3. Substitute the value of R into the equation to find I.
**Answer Field:**
- Enter your final answer for the starting current in the box below.
[Answer Box] A
(Note: This explanation assumes no external diagrams or graphs accompany the problem.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F238fed3b-2fcf-40ca-a8e1-295985b4dcab%2Fd2647304-c6eb-46ad-88b6-c83d71f771b7%2Fav0mxo_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
The motor in a toy car operates on 6.00 V, developing a 4.70 V back emf at normal speed. If it draws 3.00 A at normal speed, what current (in A) does it draw when starting?
**Solution Approach:**
- Calculate the resistance (R) using Ohm's Law at normal speed.
- Use the resistance to find the starting current, assuming no back emf at start.
**Given Data:**
- Operating voltage (V) = 6.00 V
- Back electromotive force (emf) at normal speed = 4.70 V
- Current at normal speed = 3.00 A
- Voltage across the motor at normal speed = V - Back emf
**Calculation Steps:**
1. Calculate resistance (R) at normal speed:
\[
R = \frac{V_{\text{effective}}}{I} = \frac{6.00 \text{ V} - 4.70 \text{ V}}{3.00 \text{ A}}
\]
2. Calculate starting current (I) with V = 6.00 V and no back emf:
\[
I = \frac{V}{R}
\]
3. Substitute the value of R into the equation to find I.
**Answer Field:**
- Enter your final answer for the starting current in the box below.
[Answer Box] A
(Note: This explanation assumes no external diagrams or graphs accompany the problem.)
Expert Solution
Step 1
Given that:-
Source voltage=Vs=6 V
Back emf=Vb=4.7V
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