E= 18 V 0.5 Q R 2.5 Q- R, a 6.0 2 R 1.52 h 0.5 N E, = 45 V What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? 0 = If the current through the middle part of the loop is I = 4.75 amps, what is the current through the top loop, I2, in amps? I, =
E= 18 V 0.5 Q R 2.5 Q- R, a 6.0 2 R 1.52 h 0.5 N E, = 45 V What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? 0 = If the current through the middle part of the loop is I = 4.75 amps, what is the current through the top loop, I2, in amps? I, =
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