E= 18 V 0.5 Q R 2.5 Q- R, a 6.0 2 R 1.52 h 0.5 N E, = 45 V What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? 0 = If the current through the middle part of the loop is I = 4.75 amps, what is the current through the top loop, I2, in amps? I, =

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**Circuit Diagram Explanation:**

The given circuit diagram features two voltage sources and three resistors. The labels and elements are as follows:

- **Voltage Sources:**
  - \( \mathcal{E}_1 = 18 \, \text{V} \)
  - \( \mathcal{E}_2 = 45 \, \text{V} \)

- **Resistors:**
  - \( R_1 = 6.0 \, \Omega \)
  - \( R_2 = 2.5 \, \Omega \)
  - \( R_3 = 1.5 \, \Omega \)
  - Additionally, there are resistors \( r_1 \) and \( r_2 \) in the diagram, each \( 0.5 \, \Omega \).

- **Current Directions and Variables:**
  - \( I_1 \), \( I_2 \), and \( I_3 \) represent currents through different sections of the circuit.
  - The currents are indicated by arrows, and the loop is traced aedcba.

**Question on Loop Rule:**

- **Task:** Find the equation for the loop aedcba using the loop rule (Kirchhoff's voltage law), expressing the equation in terms of the variables given in the figure.

- **Equation:** 
  - \( 0 = \)

**Current Calculation:**

- **Task:** If the current through the middle part of the loop, \( I_1 \), is \( 4.75 \, \text{A} \), determine the current through the top loop, \( I_2 \).

- **Current \( I_2 \):**
  - \( I_2 = \)
Transcribed Image Text:**Circuit Diagram Explanation:** The given circuit diagram features two voltage sources and three resistors. The labels and elements are as follows: - **Voltage Sources:** - \( \mathcal{E}_1 = 18 \, \text{V} \) - \( \mathcal{E}_2 = 45 \, \text{V} \) - **Resistors:** - \( R_1 = 6.0 \, \Omega \) - \( R_2 = 2.5 \, \Omega \) - \( R_3 = 1.5 \, \Omega \) - Additionally, there are resistors \( r_1 \) and \( r_2 \) in the diagram, each \( 0.5 \, \Omega \). - **Current Directions and Variables:** - \( I_1 \), \( I_2 \), and \( I_3 \) represent currents through different sections of the circuit. - The currents are indicated by arrows, and the loop is traced aedcba. **Question on Loop Rule:** - **Task:** Find the equation for the loop aedcba using the loop rule (Kirchhoff's voltage law), expressing the equation in terms of the variables given in the figure. - **Equation:** - \( 0 = \) **Current Calculation:** - **Task:** If the current through the middle part of the loop, \( I_1 \), is \( 4.75 \, \text{A} \), determine the current through the top loop, \( I_2 \). - **Current \( I_2 \):** - \( I_2 = \)
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