The liquid food is heated in a tubular heat exchanger. The inside pipe wall temperature is 110 °C. The internal diameter of the pipe is 50 mm. The product flows at 0.7 kg/s. If the initial temperature of the product is 7 °C, calculate the convective heat transfer coefficient. The thermal properties of the product are as follows: specific heat = 3.7 kJ / (kg °C), thermal conductivity = 0.6 W / (m °C), product viscosity = 500 x 10-6 Pa s, density = 1000 kg / m³ , product viscosity at 110 °C = 410 x 10-6 Pa s. a. Determine Reynolds number = Answer 35668.7898 . b. Determine the number Prantl = Answer 3.083 . c. Determine Nuselt number = Answer d. Convection coefficient = Answer
The liquid food is heated in a tubular heat exchanger. The inside pipe wall temperature is 110 °C. The internal diameter of the pipe is 50 mm. The product flows at 0.7 kg/s. If the initial temperature of the product is 7 °C, calculate the convective heat transfer coefficient. The thermal properties of the product are as follows: specific heat = 3.7 kJ / (kg °C), thermal conductivity = 0.6 W / (m °C), product viscosity = 500 x 10-6 Pa s, density = 1000 kg / m³ , product viscosity at 110 °C = 410 x 10-6 Pa s. a. Determine Reynolds number = Answer 35668.7898 . b. Determine the number Prantl = Answer 3.083 . c. Determine Nuselt number = Answer d. Convection coefficient = Answer
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The liquid food is heated in a tubular heat exchanger. The inside pipe wall temperature is 110 °C. The internal diameter of the pipe is 50 mm. The product flows at 0.7 kg/s. If the initial temperature of the product is 7 °C, calculate the convective heat transfer coefficient. The thermal properties of the product are as follows: specific heat = 3.7 kJ / (kg °C), thermal conductivity = 0.6 W / (m °C), product viscosity = 500 x 10-6 Pa s, density = 1000 kg / m³ , product viscosity at 110 °C = 410 x 10-6 Pa s.
a. Determine Reynolds number = Answer
35668.7898
.
b. Determine the number Prantl = Answer
3.083
.
c. Determine Nuselt number = Answer
d. Convection coefficient = Answer
W/m² °C.
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