the level of significance is 0.05, and the P-value is 0.043, the decision would be to... 1. reject the null hypothesis. 2. make no decision because the difference between the level of significance and the p-value is not statistically significant. 3. use a nonparametric test because normality of the data cannot be established when the results are close. 4. fail to reject the null
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If the level of significance is 0.05, and the P-value is 0.043, the decision would be to...
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- A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? A. Ho: H#H2 OB. Ho: H1 H₂ H₁: H₁ H₂ H₁: H₁ H₂ D. Ho: ₁ = ₂ C. Ho: ₁ = ₂ H₁: µ₁ ‡µ₂ H₁: H₁ H₂ The test statistic, t, is . (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) ESIX n H₂ Treatment Placebo H₁ 28 2.36 36 2.61 0.96 S 0.66If a significance test gives p-value 0.005... A.. the effect of interest is practically significant B...We do have good evidence against the null hypothesis C...we do not have good evidence against the null hypothesis D...the null hypothesis is very likely to be true E.. The margin of error is 0.005Suppose the level of significance α was 0.10 and the p-value is 0.084 The conclusion would be to... Fail to reject the null hypothesis Reject the null hypothesis Reject the alternative hypothesis Accept the alternative hypothesis Accept the null hypothesis
- Casey is a statistics student who is conducting a one-sample z‑test for a population proportion p using a significance level of a=. Her null (H0) and alternative (Ha) hypotheses are H0:p=0.094Ha:p≠0.094 The standardized test statistic is z = 1.40. What is the P-value of the test? P-value =The mean GPA of night students is significantly different than the mean GPA of day students at the 0.01 significance level. Null and alternative hypothesis? H0:μN=μD H1:μN≠μD When it says "significantly different" would we choose the option with the line going through the equal sign? The test is: two-tailed (Is this the choice for a hypothesis that has an equal sign with the line through it? left-tailed right-tailed Sample of 75-night students, a sample mean GPA of 3.47 and an SD of 0.03 Sample of 35-day students, a sample mean GPA of 3.45 and an SD of 0.04. The test statistic is: Do we use the z test or interval function on the calculator? The positive critical value is: How do we solve for critical value and then use this info to figure out if the hypothesis was rejected or failed? < Based on this we: Reject the null hypothesis OR Fail to reject the null hypothesisProfessor Nord stated that the mean score on the final exam from all the years he has been teaching is a 79%. Colby was in his most recent class, and his class’s mean score on the final exam was 82%. Colby decided to run a hypothesis test to determine if the mean score of his class was significantly greater than the mean score of the population. α = .01. What is the null hypothesis in this case? If p = 0.29, should Colby reject or fail to reject the null hypothesis? What should Colby’s statement of conclusion be? (This circles back to what is being tested).
- Q10. For a hypothesis test about a population mean, if the level of significance is 0.05 and the P-value is 0.50, then we fail to reject the null hypothesis. a. Trueb. FalseThe P-value for a hypothesis test is 0.068. For each of the following significance levels, decide whether the null hypothesis should be rejected. a. α = 0.05 b. x = 0.10 a. Determine whether the null hypothesis should be rejected for x = 0.05. A. Reject the null hypothesis because the P-value is greater than the significance level. B. Reject the null hypothesis because the P-value is equal to or less than the significance level. C. Do not reject the null hypothesis because the P-value is greater than the significance level. D. Do not reject the null hypothesis because the P-value is equal to or less than the significance level. b. Determine whether the null hypothesis should be rejected for x = 0.10. A. Do not reject the null hypothesis because the P-value is equal to or less than the significance level. B. Reject the null hypothesis because the P-value is equal to or less than the significance level. C. Do not reject the null hypothesis because the P-value is greater than the…Newspaper headlines at the time and traditional wisdom in the succeeding decades have held that women and children escaped a sunken ship in greater proportion than men. Here's a table with the relevant data. Do you think that survival was independent of whether the person was male or female? Defend your conclusion. A. Is there evidence of a significant difference between the proportion of males and females who survived at the 0.005 level of significance? What are the null and alternative hypotheses to test? B. Are the conditions for inference satisfied? C. Calculate the test statistic D. Determine the P-value and interpret the meaning E. Reject or Fail to Reject and why?
- 2. Suppose a 95% CI for the proportion of adults that regularly attend a tae kwon do class at least once a week was found to be (0.2534, 0.3894). decision a. For the null and alternative hypothesis: Ho: p = 0.40 versus Ha: p # 0.40, what is for this test of hypothesis? your b. Based on the CI, which of the following statements gives the best conclusion about the true value of the proportion of adults that regularly attend a tae kwon do class at least once a week? i. I am 95% confident that the proportion of adults that regularly attend a tae kwon do class at least once a week is greater than 40%. ii. I am 95% confident that the proportion of adults that regularly attend a tae kwon do class at least once a week is different than 40% iii. I am 95% confident that the proportion of adults that regularly attend a tae kwon do class at least once a week is less than 40% iv. I am 95% confident that the proportion of adults that regularly attend a tae kwon do class at least once a week equals…A news article that you read stated that 52% of voters prefer the Democratic candidate. You think that the actual percent is larger. 149 of the 266 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.05 level of significance? The p-value is ? ≤ > αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger 52% at αα = 0.05, so there is not sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is larger 52%. The data suggest the population proportion is not significantly larger 52% at αα = 0.05, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is equal to 52%. The data suggest the populaton proportion is significantly larger 52% at αα = 0.05, so there is sufficient evidence to conclude…Determine the null and alternative hypotheses. Choose the correct choice below. A. H0: The distribution of the variable is the same as the given distribution. Ha: The distribution of the variable differs from the given distribution. answer is correct. B. H0: The distribution of the variable differs from the normal distribution. Ha: The distribution of the variable is the normal distribution. C. H0: The distribution of the variable differs from the given distribution. Ha: The distribution of the variable is the same as the given distribution. D. H0: The expected frequencies are all equal to 5. Ha: At least one expected frequency differs from 5. Compute the value of the test statistic, χ2. χ2= (Round to three decimal places as needed.) Find the P-value. P= (Round to three decimal places as needed.) Does the data provide sufficient evidence that the distribution of the variable differs from the given distribution?…