the level of significance is 0.05, and the P-value is 0.043, the decision would be to... 1. reject the null hypothesis. 2. make no decision because the difference between the level of significance and the p-value is not statistically significant. 3. use a nonparametric test because normality of the data cannot be established when the results are close. 4. fail to reject the null

the level of significance is 0.05, and the P-value is 0.043, the decision would be to... 1. reject the null hypothesis. 2. make no decision because the difference between the level of significance and the p-value is not statistically significant. 3. use a nonparametric test because normality of the data cannot be established when the results are close. 4. fail to reject the null

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter4: Equations Of Linear Functions

Section: Chapter Questions

Problem 8SGR

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Use a 0.05 significance level to test the claim that there is a difference between the actual and reported heights, in inches, for 12-16 year old boys. The data is listed in the table below. Click the icon to view the data table of the reported heights. Let μ₁ denote the median of the first variable and μ₂ denote the median of the second variable. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ C. Ho: H₁ H2 H₁: H₁ H₂ Find the test statistic. Test statistic = -2.26 (Round to two decimal places as needed.) CH More Info OB. Ho: H₁ H₂ H₁: P1 P₂ OD. Ho: ₁2H₂ H₁ H₁ H₂ Actual 61.9 67.9 71.2 61.4 62.3 68.8 65.9 70.8 61.9 66.7 Reported 62 68 71 62 61 69 66 70 62 67 Actual 59.6 71.9 64.5 64.4 71.9 69.1 68.8 68.1 71.7 62.5 Reported 60 72 64 64 72 69 68 68 72 62 Actual 65.2 59.9 64.8 65.5 67 Reported 65 60 65 66 67 Print 68.7 65.2 71.4 69.2 60.9 69 65 72 69 61 Done - X
Suppose the level of significance α was 0.10 and the p-value is 0.084 The conclusion would be to... Fail to reject the null hypothesis Reject the null hypothesis Reject the alternative hypothesis Accept the alternative hypothesis Accept the null hypothesis
Casey is a statistics student who is conducting a one-sample z‑test for a population proportion p using a significance level of a=. Her null (H0) and alternative (Ha) hypotheses are H0:p=0.094Ha:p≠0.094 The standardized test statistic is z = 1.40. What is the P-value of the test? P-value =
The mean GPA of night students is significantly different than the mean GPA of day students at the 0.01 significance level. Null and alternative hypothesis? H0:μN=μD H1:μN≠μD When it says "significantly different" would we choose the option with the line going through the equal sign? The test is: two-tailed (Is this the choice for a hypothesis that has an equal sign with the line through it? left-tailed right-tailed Sample of 75-night students, a sample mean GPA of 3.47 and an SD of 0.03 Sample of 35-day students, a sample mean GPA of 3.45 and an SD of 0.04. The test statistic is: Do we use the z test or interval function on the calculator? The positive critical value is: How do we solve for critical value and then use this info to figure out if the hypothesis was rejected or failed? < Based on this we: Reject the null hypothesis OR Fail to reject the null hypothesis
Q10. For a hypothesis test about a population mean, if the level of significance is 0.05 and the P-value is 0.50, then we fail to reject the null hypothesis. a. Trueb. False
The P-value for a hypothesis test is 0.068. For each of the following significance levels, decide whether the null hypothesis should be rejected. a. α = 0.05 b. x = 0.10 a. Determine whether the null hypothesis should be rejected for x = 0.05. A. Reject the null hypothesis because the P-value is greater than the significance level. B. Reject the null hypothesis because the P-value is equal to or less than the significance level. C. Do not reject the null hypothesis because the P-value is greater than the significance level. D. Do not reject the null hypothesis because the P-value is equal to or less than the significance level. b. Determine whether the null hypothesis should be rejected for x = 0.10. A. Do not reject the null hypothesis because the P-value is equal to or less than the significance level. B. Reject the null hypothesis because the P-value is equal to or less than the significance level. C. Do not reject the null hypothesis because the P-value is greater than the…
Use a significance level of a=0.05 to test the claim that u = 20.0. The sample data consists of 10 scores for which x =20.5 ands=4.5. State the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. State your conclusions about the claim. Ho:=20.0 H: p 20.0 O Test statistic: t=0.3514. P-Value: P= 0.7334. Accept H, : µ = 20.0. Since P>a, thère is not sufficient evidence to support the claim that the mean is different from 20.0. H:p=20.0 H,: p 20.0 O Test statistic: t=0.3514. P-Value: P 0.7334. Reject H: = 20.0. Since P>a, there is sufficient evidence to support the claim that the mean is different from 20.0. Ho: H=20.0 H : p= 20.0 O Test statistic: t=0.3514. P-Value: P= 0.3667. Accept H:H = 20.0. Since P>a, there is not sufficient evidence to support the claim that the mean is different from 20.0. H: p= 20.5 H,:u 20.5
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The critical boundaries for a hypothesis test are z = +1.96 and z = -1.96. If the z-score for the sample data is z = -1.90, which is the correct statistical decision? a. fail to reject H1 b. fail to reject H0 c. reject H0 d. reject H1
The P-value for a hypothesis test is 0.081. For each of the following significance levels, decide whether the null hypothesis should be rejected. a. a = 0.05 b. a = 0.10 a. Determine whether the null hypothesis should be rejected for a = 0.05. O A. Reject the null hypothesis because the P-value is equal to or less than the significance level. B. Reject the null hypothesis because the P-value is greater than the significance level. C. Do not reject the null hypothesis because the P-value is greater than the significance level. D. Do not reject the null hypothesis because the P-value is equal to or less than the significance level.
Men Women H2 A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. 11 97.73°F 0.95°F 59 97.21°F 0.66°F a. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? O A. Ho: H12H2 H1: H1 H2 The test statistic, t, is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.)
A poll of 2,122 randomly selected adults showed that 93% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.92 vs p *0.92 Sample X 1 N 2,122 1970 Sample p 0.928369 95% CI The P-value is (Round to three decimal places as needed.) (0.917397,0.939341) a. Is the test two-tailed, left-tailed, or right-tailed? O Two-tailed test O Left-tailed test O Right tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? Z-Value 1.42 P-Value 0.155