Consider a multinomial experiment with n=320 and k=4. The null hypothesis to be tested is Hg: P1 = P2 P3 P4 = 0.25. Theobserved frequencies resulting from the experiment are: (You may find it useful to reference the appropriate table: chi-square taor E table)CategoryFrequency488539089a. Choose the appropriate alternative hypothesis.O Not all population proportions are equal to 0.25.O All population proportions differ from 0.25.b-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3decimal places.)Test statistic< Prev.Next >4 of 10aere to search b-2. Find the p-value.O 0.025 B p-value < 0.05O p-value <0.01O 0.015 p-value <0.025p-value 0.10O 0.05 p-value <0.10c. At the 10% significance level, what is the conclusion to the hypothesis test?O Reject Hg since the p-value is greater than the significance level.O Do not reject Hg since the p-value is greater than the significance level.O Reject Hg since the p-value is less than the significance level.O Do not reject H, since the p-value is less than the significance level.rev: 06 10 2019 QC_CS-170121, 07 23 2020 QC CS-220209Prev4 of 10Next- search

We are testing that if all proportion are 0.25 or not for that we will use chi square goodness of…

Consider a multinomial experiment with n=320 and k=4. The null hypothesis to be tested is Hg: P1 = P2 P3 P4 = 0.25. The observed frequencies resulting from the experiment are: (You may find it useful to reference the appropriate table: chi-square to or F table) Category Frequency 1 4 88 53 90 89 a. Choose the appropriate alternative hypothesis. O Not all population proportions are equal to 0.25. O All population proportions differ from 0.25. b-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic

Consider a multinomial experiment with n=320 and k=4. The null hypothesis to be tested is Hg: P1 = P2 P3 P4 = 0.25. The observed frequencies resulting from the experiment are: (You may find it useful to reference the appropriate table: chi-square to or F table) Category Frequency 1 4 88 53 90 89 a. Choose the appropriate alternative hypothesis. O Not all population proportions are equal to 0.25. O All population proportions differ from 0.25. b-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Chapter 9: Hypothesis Tests for a Single Population Proportion Score: 4/14 4/14 answered Question 1 Test the claim that the proportion of men who own cats is smaller than 20% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p > 0.2 Ho:p= 0.2 Ho:p 0.2 H1:p 0.2 H1:µ 7 0.2 H1:µ > 0.2 H1:p< 0.2 The test is: two-tailed left-tailed right-tailed Based on a sample of 600 people, 15% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: Message instructor Submit Question ch
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If Lynell requires her results to be statistically significant at level ?=0.05α=0.05, choose the correct decision for her to make about this test, along with the correct reason for making that decision. Reject ?0H0, because the ?P-value is less than 0.05. Fail to reject ?0H0, because the the difference between the sample count and the expected count is −12.00−12.00, which is too small to be significant. Fail to reject ?0H0, because the ?P-value is less than 0.05. Reject ?0H0, because the ?P-value is greater than 0.01.
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The one-sample ?‑statistic for a test of ?0:?=0 versus ?1:?≠0 based on ?=15 observations has the value ?=−2.138, where ?0 and ?1 are the null and alternative hypotheses, respectively. The sample size is denoted by ?. Use this ?‑table to determine which two ?-values bracket the ?-value of the test. Report your answer as listed in the given ?‑table.
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Do question 7,8 and 9 only The new study also carried out a test to determine whether the population proportion of unvaccinated school children contracting winter flu was higher than the population proportion of vaccinated school children. The Z test statistic to test this belief is found to be 1.874. The corresponding p-value is 0.0305 0.1212 0.3036 0.7724 Question 7 Suppose that the new study uses a level of significance of 0.05 to test the claim in Question 6. The probability of Type I error is 0.025 0.05 0.95 0.975 Question 8 Based on previous studies of school children who were vaccinated and contracted the flu, the time in hours that the flu symptoms last is assumed to follow a normal distribution with a mean of 20.7 hours and a standard deviation of 7.3 hours. The probability that a randomly selected school child has flu symptoms for more than 24 hours is 0.1628 0.3256 0.6744 0.8372 Question 9 Suppose that a random sample of 5 vaccinated school children is taken. Assuming the…
We have provided a sample mean, sample size, and population standard deviation. In each case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level. x = 20, n = 24, σ = 4, H0: μ = 22, Ha: μ ≠ 22
A sample is selected from a normal population with µ = 54 and σ = 8. Which of the following samples would be considered extreme and unrepresentative for this population? A. M = 53 and n = 81 B. M = 52 and n = 36 C. M = 53 and n = 36 D. M = 52 and n = 81
1.18 Cats on YouTube. Suppose you want to estimate the percentage of videos on YouTube that are cat videos. It is impossible for you to watch all videos on YouTube so you use a random video picker to select 1000 videos for you. You find that 2% of these videos are cat videos. Determine which of the following is an observation, a variable, a sample statistic (value calculated based on the observed sample), or a population parameter
A news article that you read stated that 51% of voters prefer the Democratic candidate. You think that the actual percent is larger. 139 of the 262 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger 51% at αα = 0.10, so there is sufficient…
You may need to use the appropriate technology to answer this question. Submitted The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A B C P 20 44 50 Q 30 26 30 Test for independence of the row and column variables using a = 0.05. State the null and alternative hypotheses. Ho: The column variable is independent of the row variable. H: The column variable is not independent of the row variable. Ho: Variable P is not independent of variable Q. H: Variable P is independent of variable Q. Ho: Variable P is independent of variable Q. H: Variable P is not independent of variable Q. : The column variable is not independent of the row variable. Ho: : The column variable is independent of the row variable. Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value %3D State your conclusion. Reject Ho. We conclude that the column and row variables are…