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- Please see attached.101 Chem101 C Itu Tieleionuelear Diatomic Mol x b My Questions | bartleby X G 12 - Google Search -> app.101edu.co M Apps G M Gmail YouTube Maps а АМAZON Translate Gflights USCIS Ь ВАТERBLY C CHEGG > KATAPULK CUBA SUPERMARKET23 Essay Writing Ser... G calculator - Googl... Reading List Question 17 of 22 Submit Complete the MO diagram (below) to determine if I, is paramagnetic or diamagnetic. Op - Tp Tp A) paramagnetic Op B) diamagnetic Os +Which of the following are enantiomers of each other? H H H H H ... A Br H 114 B F Br Br C Vill H H Т Br ... I D F H
- 6. A 15.00 g sample of an oxide of nitrogen is heated and decomposes to nitrogen and oxygen. All the oxygen is removed and 3.89 g of nitrogen remains. a. What mass of oxygen was also formed when the sample decomposed?A and B6 Kronos Workforce.. ervice inte... (Last Day Promotio... [References] Given the following data 2 CIF(g) +O2 (g) Cb O(g) +F20(g) 2 CIF3 (g) + 202(g) Cl2 O(g)+ 3F20(g) 2F2 (g) + O2 (g) 2F20(g) AH= 167.4 kJ AH=341.4 kJ AH=-43.4 kJ calculate A H for the reaction CIF(g) +F2 (g) CIF3 (g) AH= kJ Try Another Version 1 item attempt remaining Submit Answer
- 2. Two common air pollutants when analyzed yield the following information; Compound I shows that 1 gram of sulfur combines with 1 gram of oxygen. Compound II shows that 1.5 grams of oxygen combines with 1 gram of sulfur. This is consistent with the law of because... a) the analysis shows that sulfur and oxygen can combine in more than one way. b) the analysis shows that the combination of sulfur and oxygen is very close to 1 in both cases. c) the analysis shows that a small whole number (2) could be used to make a ratio of 2:3 for the oxygen mass in compound I compared to compound II.Which equation states the law of conservation of energy? O A. AE = q + w O B. E = mc- O C. E = /2mv2 O D. w = PAV O E. E= hc/(please type answer)
- Q1-Complete the blanks? 1-Major categories of gaseous atmospheric chemical species are................. 2-An atmospheric molecule designated by an asterisk, such as NO2*, is...................Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…Q 15: Identify the Intermolecular forces (IMF) present in the following molecules: a. PH3 b. CH3CH2OH c. Fr2S d. AsBr3 Q 16: Assess which combination of quantum numbers are correct. If not make the correction. a. (5,1,0,1/2) b. (2,0,2,1/2 с. (1, 0,1,-1/2) d. (4,-1,0,1/2) е. (3, 2, -1, 1/2 f. (1, 0, 0, 1) Q 17: Predict the hybridization of central atom, and describe the 3D shapes of the following: a. Sels b. AsH3