The internal energy of a system changes because the system gains 156 J of heat and performs 309 J of work. In returning to its initial state, the system loses 124 J of heat. During this return process, what work is involved? If the work is done by the system, then give the work involved as a positive number. If the work is done on the system, then give the work involved as a negative number.Number [Text box] Units [Drop-down menu]

Answered: The internal energy of a system changes…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The internal energy of a system changes because the system gains 156 J of heat and performs 309 J of work. In returning to its initial state, the system loses 124 J of heat. During this return process, what work is involved? If the work is done by the system, then give the work involved as a positive number. If the work is done on the system, then give the work involved as a negative number.

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Expert Solution

Step 1

Given,

Heat gain $Q = 156 J$

Work $W = 309 J$

According to the first law of thermodynamics

$∆ U = Q - W$

where,

$∆ U$ is the change in internal energy

According to the problem, the system comes back into initial state , which implies the internal energy of the system which is a state function will remain unchanged.

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