The burner in a hot air balloon adds 6400 J of heat to the balloon while the ballon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon?
The burner in a hot air balloon adds 6400 J of heat to the balloon while the ballon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Question:**
The burner in a hot air balloon adds 6400 J of heat to the balloon while the balloon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon?
A. + 6400 J
B. - 3300 J
C. + 9500 J
D. + 3300 J
**Explanation:**
This is a physics problem that deals with the First Law of Thermodynamics, which states that the change in internal energy (\(\Delta U\)) of a system is equal to the heat added to the system (\(Q\)) minus the work done by the system (\(W\)):
\[
\Delta U = Q - W
\]
In this scenario:
- The heat added to the balloon, \(Q\), is 6400 J.
- The work done by the balloon on the surrounding air, \(W\), is 3100 J.
Using the formula:
\[
\Delta U = 6400\, \text{J} - 3100\, \text{J} = 3300\, \text{J}
\]
Therefore, the internal change in thermal energy of the balloon is \(+3300\, \text{J}\).
The correct answer is D. + 3300 J.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab8e90de-1834-4897-8d02-45bfaff51002%2F15a71297-3769-4667-aa6c-f612eea45d4e%2Fg5o3gn_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
The burner in a hot air balloon adds 6400 J of heat to the balloon while the balloon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon?
A. + 6400 J
B. - 3300 J
C. + 9500 J
D. + 3300 J
**Explanation:**
This is a physics problem that deals with the First Law of Thermodynamics, which states that the change in internal energy (\(\Delta U\)) of a system is equal to the heat added to the system (\(Q\)) minus the work done by the system (\(W\)):
\[
\Delta U = Q - W
\]
In this scenario:
- The heat added to the balloon, \(Q\), is 6400 J.
- The work done by the balloon on the surrounding air, \(W\), is 3100 J.
Using the formula:
\[
\Delta U = 6400\, \text{J} - 3100\, \text{J} = 3300\, \text{J}
\]
Therefore, the internal change in thermal energy of the balloon is \(+3300\, \text{J}\).
The correct answer is D. + 3300 J.
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