The burner in a hot air balloon adds 6400 J of heat to the balloon while the ballon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon?

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Chapter1: Units, Trigonometry. And Vectors
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**Question:**

The burner in a hot air balloon adds 6400 J of heat to the balloon while the balloon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon?

A. + 6400 J  
B. - 3300 J  
C. + 9500 J  
D. + 3300 J

**Explanation:**

This is a physics problem that deals with the First Law of Thermodynamics, which states that the change in internal energy (\(\Delta U\)) of a system is equal to the heat added to the system (\(Q\)) minus the work done by the system (\(W\)):

\[
\Delta U = Q - W
\]

In this scenario:
- The heat added to the balloon, \(Q\), is 6400 J.
- The work done by the balloon on the surrounding air, \(W\), is 3100 J.

Using the formula:
\[
\Delta U = 6400\, \text{J} - 3100\, \text{J} = 3300\, \text{J}
\]

Therefore, the internal change in thermal energy of the balloon is \(+3300\, \text{J}\).

The correct answer is D. + 3300 J.
Transcribed Image Text:**Question:** The burner in a hot air balloon adds 6400 J of heat to the balloon while the balloon expands. As the balloon expands, it does 3100 J of work on the surrounding air. What is the internal change in thermal energy of the balloon? A. + 6400 J B. - 3300 J C. + 9500 J D. + 3300 J **Explanation:** This is a physics problem that deals with the First Law of Thermodynamics, which states that the change in internal energy (\(\Delta U\)) of a system is equal to the heat added to the system (\(Q\)) minus the work done by the system (\(W\)): \[ \Delta U = Q - W \] In this scenario: - The heat added to the balloon, \(Q\), is 6400 J. - The work done by the balloon on the surrounding air, \(W\), is 3100 J. Using the formula: \[ \Delta U = 6400\, \text{J} - 3100\, \text{J} = 3300\, \text{J} \] Therefore, the internal change in thermal energy of the balloon is \(+3300\, \text{J}\). The correct answer is D. + 3300 J.
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