# Heat Engine Problem**Problem Statement:**1. A heat engine takes in 90W of power from the hot reservoir and deposits 60W of power into the cold reservoir. - a. How much work does the engine do? - b. What is the efficiency of this engine?**Explanation:**The problem involves a heat engine that absorbs energy from a hot reservoir and expels energy into a cold reservoir. The amount of work done by the engine and its efficiency need to be calculated based on the given values.**Key Concepts:**- **Work Done (W):** In a heat engine, the work done is the difference between the energy absorbed from the hot reservoir and the energy expelled to the cold reservoir. - **Efficiency (η):** The efficiency of a heat engine is defined as the ratio of the work done by the engine to the energy absorbed from the hot reservoir. - **Formulae:** - Work Done \( W = Q_{\text{in}} - Q_{\text{out}} \) - Efficiency \( η = \frac{W}{Q_{\text{in}}} \)**Solution Steps:**1. Calculate the work done using the formula: - \( W = 90\,\text{W} - 60\,\text{W} = 30\,\text{W} \)2. Calculate the efficiency using the formula: - \( η = \frac{30\,\text{W}}{90\,\text{W}} \) - \( η = \frac{1}{3} \) - Convert to percentage: \( η = \frac{1}{3} \times 100\% = 33.33\% \)**Conclusion:**Thus, the engine does 30W of work, and the efficiency of the engine is 33.33%.

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1. A heat engine takes in 90W of power from the hot reservoir and deposits 60W of power into the cold reservoir. a. How much work does the engine do? b. What is the efficiency of this engine? of the water what is the temperature of veter och

1. A heat engine takes in 90W of power from the hot reservoir and deposits 60W of power into the cold reservoir. a. How much work does the engine do? b. What is the efficiency of this engine? of the water what is the temperature of veter och

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

First law of Thermodynamics

The word thermodynamics consists of two words: thermo- and dynamics. Dynamics means the study of motion. The field of thermodynamics is all about the study of the movement of heat. In a more meaningful way, it is stated as the study of the transfer of energy. Energy transfer is something that we encounter in day-to-day life. Automobiles, chemical reactions, refrigerators, and power generators work on the basis of thermodynamic principles.

Question

# Heat Engine Problem

**Problem Statement:**

1. A heat engine takes in 90W of power from the hot reservoir and deposits 60W of power into the cold reservoir.
- a. How much work does the engine do?
- b. What is the efficiency of this engine?

**Explanation:**

The problem involves a heat engine that absorbs energy from a hot reservoir and expels energy into a cold reservoir. The amount of work done by the engine and its efficiency need to be calculated based on the given values.

**Key Concepts:**

- **Work Done (W):** In a heat engine, the work done is the difference between the energy absorbed from the hot reservoir and the energy expelled to the cold reservoir.

- **Efficiency (η):** The efficiency of a heat engine is defined as the ratio of the work done by the engine to the energy absorbed from the hot reservoir.

- **Formulae:**
- Work Done \( W = Q_{\text{in}} - Q_{\text{out}} \)
- Efficiency \( η = \frac{W}{Q_{\text{in}}} \)

**Solution Steps:**

1. Calculate the work done using the formula:
- \( W = 90\,\text{W} - 60\,\text{W} = 30\,\text{W} \)

2. Calculate the efficiency using the formula:
- \( η = \frac{30\,\text{W}}{90\,\text{W}} \)
- \( η = \frac{1}{3} \)
- Convert to percentage: \( η = \frac{1}{3} \times 100\% = 33.33\% \)

**Conclusion:**

Thus, the engine does 30W of work, and the efficiency of the engine is 33.33%.

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