The graph shows the x-directed force Fg acting on an object as a function of the position x of the object. For each numbered interval given, find the work W; done on the object. 4 2- 1) from x = 0 m to x = 2.70 m 0- x(m) A 3 6 i 8 9 10 -2 W, = 10.2 J 2) from x = 3.00 m to x = 5.70 m W2 = J 3) from x = 7.00 m to x = 9.10 m W3 J 9. (N)'1
The graph shows the x-directed force Fg acting on an object as a function of the position x of the object. For each numbered interval given, find the work W; done on the object. 4 2- 1) from x = 0 m to x = 2.70 m 0- x(m) A 3 6 i 8 9 10 -2 W, = 10.2 J 2) from x = 3.00 m to x = 5.70 m W2 = J 3) from x = 7.00 m to x = 9.10 m W3 J 9. (N)'1
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Energy Of A System
Section: Chapter Questions
Problem 25P: A force F=(4xi+3yj), where F is in newtons and x and y are in meters, acts on an object as the...
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Question
![The graph shows the x-directed force F, acting on an object
as a function of the position x of the object. For each
6-
numbered interval given, find the work W; done on the object.
4
1) from x = 0 m to x = 2.70 m
x(m)
2
3 6 i 8 9 10
-2
W¡ =
10.2
-4
-6
2) from x = 3.00 m to x = 5.70 m
W2 =
J
3) from x = 7.00 m to x = 9.10 m
W3 =
J
* TOOLS
х10
2.
(N)'I](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5df190a0-0135-412b-8287-5a70a7487817%2Facb3855e-ff75-40ae-b79a-c608d2540a6e%2F3xmz9km_processed.png&w=3840&q=75)
Transcribed Image Text:The graph shows the x-directed force F, acting on an object
as a function of the position x of the object. For each
6-
numbered interval given, find the work W; done on the object.
4
1) from x = 0 m to x = 2.70 m
x(m)
2
3 6 i 8 9 10
-2
W¡ =
10.2
-4
-6
2) from x = 3.00 m to x = 5.70 m
W2 =
J
3) from x = 7.00 m to x = 9.10 m
W3 =
J
* TOOLS
х10
2.
(N)'I
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