The graph shows the x-directed force F, acting on an object as a function of the position x of the object. For each 6- numbered interval given, find the work W; done on the object. 4- 2- 1) from x = 0 m to x = 2.70 m x(m) 0- F. 8. 10 -2 - W = J -4 - -6 2) from x = 3.00 m to x = 6.70 m J W2 = 3) from x = 7.00 m to x = 9.50 m J W3 = (N)*
The graph shows the x-directed force F, acting on an object as a function of the position x of the object. For each 6- numbered interval given, find the work W; done on the object. 4- 2- 1) from x = 0 m to x = 2.70 m x(m) 0- F. 8. 10 -2 - W = J -4 - -6 2) from x = 3.00 m to x = 6.70 m J W2 = 3) from x = 7.00 m to x = 9.50 m J W3 = (N)*
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Question
![The graph shows the x-directed force F, acting on an object
as a function of the position x of the object. For each
6.
numbered interval given, find the work W done on the object.
4-
2-
1) from x = 0 m to x = 2.70m
x(m)
8
9
10
-2 -
W1 =
J
-4
-6
2) from x = 3.00 m to x = 6.70 m
J
W2 =
3) from x = 7.00 m to x = 9.50 m
J
W3 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33281441-1e57-4fe7-bc2a-165fb9de3f22%2F45438a1b-0a45-4160-b0f9-f8f423f608d6%2F25frq75_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The graph shows the x-directed force F, acting on an object
as a function of the position x of the object. For each
6.
numbered interval given, find the work W done on the object.
4-
2-
1) from x = 0 m to x = 2.70m
x(m)
8
9
10
-2 -
W1 =
J
-4
-6
2) from x = 3.00 m to x = 6.70 m
J
W2 =
3) from x = 7.00 m to x = 9.50 m
J
W3 =
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