Macmillan Learning The graph shows the x-directed force F, acting on an object as a function of the position x of the object. For each numbered interval given, find the work W; done on the object. 1) from x = 0 m to x = 2.90 m W₁ = 2) from x= 3.00 m to x = 6.50 m W₂ 11 11.6 W3 = -42 Incorrect 3) from x = 7.00 m to x = 9.50 m 10 J J F,(N) 4 2 -2- + -6 7 8 9 10 x(m)
Macmillan Learning The graph shows the x-directed force F, acting on an object as a function of the position x of the object. For each numbered interval given, find the work W; done on the object. 1) from x = 0 m to x = 2.90 m W₁ = 2) from x= 3.00 m to x = 6.50 m W₂ 11 11.6 W3 = -42 Incorrect 3) from x = 7.00 m to x = 9.50 m 10 J J F,(N) 4 2 -2- + -6 7 8 9 10 x(m)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Macmillan Learning
The graph shows the x-directed force Fx acting on an object
as a function of the position x of the object. For each
numbered interval given, find the work W; done on
the object.
1) from x = 0 m to x = 2.90 m
W₁ =
2) from x = 3.00 m to x = 6.50 m
W₂ =
11.6
W3 =
-42
Incorrect
3) from x = 7.00 m to x = 9.50 m
10
F₂(N)
6-
4
2-
0
-2-
-4-
+
x(m)
7 8 9 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcc16716e-8d72-427d-9972-a87f437d269e%2F189e77a9-25d0-415f-bbbf-2c9586962921%2Fxldaw1_processed.png&w=3840&q=75)
Transcribed Image Text:Macmillan Learning
The graph shows the x-directed force Fx acting on an object
as a function of the position x of the object. For each
numbered interval given, find the work W; done on
the object.
1) from x = 0 m to x = 2.90 m
W₁ =
2) from x = 3.00 m to x = 6.50 m
W₂ =
11.6
W3 =
-42
Incorrect
3) from x = 7.00 m to x = 9.50 m
10
F₂(N)
6-
4
2-
0
-2-
-4-
+
x(m)
7 8 9 10
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