The graph shows the x-directed force Fx acting on an object as a function of the position x of the object. For each numbered interval given, find the work W; done on the object. 1) from x = 0 m to x = 2.50 m W₁ = 2) from x = 3.00 m to x = 5.90 m W₂ = 3) from x = 7.00 m to x = 9.50 m W3 = J J J F (N) 4 2- А -2- -4 -6 3 4 6 7 8 9 10 x(m)
The graph shows the x-directed force Fx acting on an object as a function of the position x of the object. For each numbered interval given, find the work W; done on the object. 1) from x = 0 m to x = 2.50 m W₁ = 2) from x = 3.00 m to x = 5.90 m W₂ = 3) from x = 7.00 m to x = 9.50 m W3 = J J J F (N) 4 2- А -2- -4 -6 3 4 6 7 8 9 10 x(m)
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![The graph shows the x-directed force Fx acting on an object
as a function of the position x of the object. For each
numbered interval given, find the work W; done on
the object.
1) from x = 0 m to x = 2.50 m
W₁
=
2) from x = 3.00 m to x = 5.90 m
W₂ =
3) from x = 7.00 m to x = 9.50 m
W3 =
J
J
J
F (N)
6
4
2-
0.
-2.
-4-
-6
2 3
5
6
7
8
9
10
x(m)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2335f6ec-42fd-4fd2-b23a-0fcd2b98790e%2F7081cdbe-25c4-43d7-91f0-0114837578ba%2Fcpexsos_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The graph shows the x-directed force Fx acting on an object
as a function of the position x of the object. For each
numbered interval given, find the work W; done on
the object.
1) from x = 0 m to x = 2.50 m
W₁
=
2) from x = 3.00 m to x = 5.90 m
W₂ =
3) from x = 7.00 m to x = 9.50 m
W3 =
J
J
J
F (N)
6
4
2-
0.
-2.
-4-
-6
2 3
5
6
7
8
9
10
x(m)
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