The gas-phase decomposition of NOBr has a k= 1.14 M-1 s-1 at 10°C. NOBr(g) → NO(g) + ½ Br2 (g) rate = k⦍NOBr⦐2 How much of the NO is produced after 1.1 min when the reaction started with 0.12 M NOBr? *round your answer up to 4 decimal places

The gas-phase decomposition of NOBr has a k= 1.14 M-1 s-1 at 10°C. NOBr(g) → NO(g) + ½ Br2 (g) rate = k⦍NOBr⦐2 How much of the NO is produced after 1.1 min when the reaction started with 0.12 M NOBr? *round your answer up to 4 decimal places

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The gas-phase decomposition of NOBr has a k= 1.14 M^-1 s^-1 at 10°C.

NOBr_(g) → NO_(g) + ½ Br_{2 (g)} rate = k⦍NOBr⦐²

How much of the NO is produced after 1.1 min when the reaction started with 0.12 M NOBr?

*round your answer up to 4 decimal places

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