For the reaction: 2N2O5(g) → 4NO2(g) + O2(g) at the time 79s when N205 is being consumed at a rate of -0.897 M/s, what is the rate at which O2 is being formed? Give a response to 4 decimal places (ignore that this is not correct in terms of significant digits - Canvas can't do significant digits). No units!
For the reaction: 2N2O5(g) → 4NO2(g) + O2(g) at the time 79s when N205 is being consumed at a rate of -0.897 M/s, what is the rate at which O2 is being formed? Give a response to 4 decimal places (ignore that this is not correct in terms of significant digits - Canvas can't do significant digits). No units!
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![For the reaction: 2N2O5(g)→ 4NO2(g) + O2(g) at the time 79s when N205 is being
consumed at a rate of -0.897 M/s, what is the rate at which O2 is being formed?
Give a response to 4 decimal places (ignore that this is not correct in terms of
significant digits - Canvas can't do significant digits). No units!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb515601b-07e7-408f-b6b4-45139ca1157c%2Fda95b190-02de-4d7a-bbd1-29a8d8c7a14c%2Fxequa0r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the reaction: 2N2O5(g)→ 4NO2(g) + O2(g) at the time 79s when N205 is being
consumed at a rate of -0.897 M/s, what is the rate at which O2 is being formed?
Give a response to 4 decimal places (ignore that this is not correct in terms of
significant digits - Canvas can't do significant digits). No units!
Expert Solution
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Step 1
We have given the following reaction
We also have given that at time of 79 s the rate of consumption of N2O5 is - 0.897 M/s
and we have asked to find out the rate of formation of O2
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Solved in 2 steps
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