Nitrogen gas N₂ and hydrogen gas H₂ combine to produce ammonia NH3 according to dy dX 1N₂ + 3H2 → 2NH3. Find r, and if ammonia is being produced at a rate of 5 moles dt dt per liter per hour. T = dY dt dX dt mol Lh mol Lh
Nitrogen gas N₂ and hydrogen gas H₂ combine to produce ammonia NH3 according to dy dX 1N₂ + 3H2 → 2NH3. Find r, and if ammonia is being produced at a rate of 5 moles dt dt per liter per hour. T = dY dt dX dt mol Lh mol Lh
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Chemical Reactions and Rates: Reaction Rate Calculations
Chemical reactions produce one or more **product** substances from one or more **reactant** substances. If *x* molecules of reactant *X* combine with *y* molecules of reactant *Y* to produce *z* molecules of product *Z*, we write the reaction as:
\[ xX + yY \rightarrow zZ \]
The reaction rate \( r \) is the rate of change of concentration of one of the products over time. For this example, we can express the rate as:
\[ r = \frac{1}{z} \frac{dZ}{dt} = - \frac{1}{y} \frac{dY}{dt} = - \frac{1}{x} \frac{dX}{dt} \]
### Example Calculation
Consider the reaction where nitrogen gas \(\text{N}_2\) and hydrogen gas \(\text{H}_2\) combine to produce ammonia \(\text{NH}_3\) according to:
\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]
Find the rates \( r \), \( \frac{dY}{dt} \), and \( \frac{dX}{dt} \) if ammonia is being produced at a rate of 5 moles per liter per hour.
**Steps:**
1. Write the given rate of production of \( \text{NH}_3 \):
\[ \frac{dZ}{dt} = 5 \text{ mol/Lh} \]
2. Calculate the reaction rate \( r \):
\[ r = \frac{1}{2} \cdot 5 = 2.5 \text{ mol/Lh} \]
3. Using \( r \) to find \( \frac{dY}{dt} \):
\[ r = \frac{1}{3} \left( -\frac{dY}{dt} \right) \]
\[ -\frac{dY}{dt} = 3 \cdot 2.5 = 7.5 \text{ mol/Lh} \]
4. Using \( r \) to find \( \frac{dX}{dt} \):
\[ -\frac{dX}{dt} = 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa2133091-a753-411c-beef-444bf7f4574e%2Fd4c54215-7682-40e7-960f-d6968c7069e8%2F5kolegk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Chemical Reactions and Rates: Reaction Rate Calculations
Chemical reactions produce one or more **product** substances from one or more **reactant** substances. If *x* molecules of reactant *X* combine with *y* molecules of reactant *Y* to produce *z* molecules of product *Z*, we write the reaction as:
\[ xX + yY \rightarrow zZ \]
The reaction rate \( r \) is the rate of change of concentration of one of the products over time. For this example, we can express the rate as:
\[ r = \frac{1}{z} \frac{dZ}{dt} = - \frac{1}{y} \frac{dY}{dt} = - \frac{1}{x} \frac{dX}{dt} \]
### Example Calculation
Consider the reaction where nitrogen gas \(\text{N}_2\) and hydrogen gas \(\text{H}_2\) combine to produce ammonia \(\text{NH}_3\) according to:
\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]
Find the rates \( r \), \( \frac{dY}{dt} \), and \( \frac{dX}{dt} \) if ammonia is being produced at a rate of 5 moles per liter per hour.
**Steps:**
1. Write the given rate of production of \( \text{NH}_3 \):
\[ \frac{dZ}{dt} = 5 \text{ mol/Lh} \]
2. Calculate the reaction rate \( r \):
\[ r = \frac{1}{2} \cdot 5 = 2.5 \text{ mol/Lh} \]
3. Using \( r \) to find \( \frac{dY}{dt} \):
\[ r = \frac{1}{3} \left( -\frac{dY}{dt} \right) \]
\[ -\frac{dY}{dt} = 3 \cdot 2.5 = 7.5 \text{ mol/Lh} \]
4. Using \( r \) to find \( \frac{dX}{dt} \):
\[ -\frac{dX}{dt} = 2
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