The function below implements Quicksort.void Quicksort (int first, int last) {int i = first+1, j = last, pivot = data[first];while (i < j) {while ((data[i] < pivot) && (i pivot) ) { j--; }if (i data[j]) {swap(&data[first], &data[j]);}if(first < j-1) { Quicksort (first, j-1); }if(j+1 < last) { Quicksort (j+1, last); }}What is worst case complexity for this algorithm?O a. O(n)O b. O(n log(n))O c.0(²)O d. O(n!)O e. O(n log(n log(n)))

It is based on divide-and-conquer technique. It chooses one element as pivot. The pivot element is…

The function below implements Quicksort. void Quicksort(int first, int last) { int i= first+1, j = last, pivot = data[first]; while (i < j) { while ((data[i] < pivot) && (i pivot) ) { j--; } if (ij) ({swap(&data[i], &data[j]); } } if (pivot>data[j]) {swap(&data[first], &data[j]);} if(first

The function below implements Quicksort. void Quicksort(int first, int last) { int i= first+1, j = last, pivot = data[first]; while (i < j) { while ((data[i] < pivot) && (i pivot) ) { j--; } if (ij) ({swap(&data[i], &data[j]); } } if (pivot>data[j]) {swap(&data[first], &data[j]);} if(first

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Answer the given question with a proper explanation and step-by-step solution. Part 1: Implement the quickselect median algorithm Implement the median algorithm from test 1, which is called the "quickselect" algorithm (due to it's relationship to quicksort). Note, it can be used to find the i-th smallest element for any value of i, but we'll just use it to find the median (i = length/2) The algorithm uses the partition helper method (provided) to find the median. The partition method moves small elements, to the left side, and big elements to the right side. Finding the median requires moving all elements smaller than the median to the left half, and all elements greater to the right half. We can call repeatedly partition in a binary-search-like manner to quickly put the median in the right place. Implement the driver method public static int median(int[] arr) which returns the median value, and modifies the input array so all small elements are in the left half, and all big elements…
please code in python Write a recursive function to add a positive integer b to another number a, add(a, b), where only the unit 1 can be added, For example add(5, 9) will return 14. The pseudocode is: # Base case: if b is 1, you can just return a + 1 # General case: otherwise, return the sum of 1 and what is returned by adding a and b - 1.
Python data structures: write a function that takes in a list (L) as input, and returns the number of inversions. An inversion in L is a pair of elements x and y such that x appears before y in L, but x > y. Your function must run in -place and implement the best possible algoritm of time complexity. def inversions(L: List) -> int:'''finds and returns number of inversions'''
main.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];
Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…
Artificial Intelligence (Part - 1) ==================== The Towers of Hanoi is a famous problem for studying recursion in computer science and searching in artificial intelligence. We start with N discs of varying sizes on a peg (stacked in order according to size), and two empty pegs. We are allowed to move a disc from one peg to another, but we are never allowed to move a larger disc on top of a smaller disc. The goal is to move all the discs to the rightmost peg (see figure). To solve the problem by using search methods, we need first formulate the problem. Supposing there are K pegs and N disk. (1) Propose a state representation for the problem?
In program C Write a recursive function find_sum(n)that calculates the sum of successive integers starting at 1and ending at n(i. e., find_sum( n) = 1 + 2 . . .+( n -1) + n.
Problem overview As you may already know from earlier courses, integer values in C++ (as well as other programming languages) are limited by the number of bits used to represent these data. For instance, a 64-bit unsigned integer has the maximum value of 2^64 - 1 or 18446744073709551615. One method of representing integers of arbitrary length, which was covered last spring, is a a linked list data structure such that that a node in the linked list corresponds to a single digit in the integer. For instance, the number 123 can be stored as linked-list that could look like this: [ 3 ] -> [ 2 ] -> [ 1 ] -> NULLNote that the first (or head) node in this list contains the least significant digit (in this case 3), while the last node contains the most significant digit (1). For this problem, you are to read in pairs of arbitrary length integers and produce correct output as outlined below. InspirationNote, this problem is inspired by Problem 8.19 from Elements of Programming…
Recursive Max! Write a recursive function rc_max(L:List[int]) -> int that takes a list L and returns an element with highest value in the list. For example, rc_max([1,2,3]) returns 3. Note that L is not necessarily sorted. You may assume that the input L is not empty. You cannot use the built-in max() Your Answer: 1 # Put your answer here 2 Submit
Q2) Draw program graph for the following code segment then calculate the cyclomatic complexity of the graph. int sea(int[] nums, int item) { int asize = nums.length; int bsize = (int)Math.floor(Math.sqrt(asize)); int pitem = 0; while (nums[Math.min(bsize, asize)-1] = asize) return -1; } while (nums[pitem] < item){ pitem ++; if (pitem == Math.min(bsize, asize)) return -1; if (nums[pitem] == item) return pitem; return -1;