12.14 Zylab 3 - Single Procedure Call Given an array of at least one integer, write a program to create a new array with elements equal to the power of each element in the original array raised to the index, i.e., P[i] = A[i]^i. For this, write two functions that will be called in main function independently. • power o inputs: element (A[i]) and index (1) • task: returns the value of element raised to index (A[i]^i). } • newElement o inputs: base address of new array P (*P), current size of P (variable k) and the new element (A[i]^i) • task: add the new element at the end. o This function does not return any value (void). Following is a sample C code to perform the required task. You may modify the code for the functions, but the task performed should not be changed. int main() { // Variable int *A, *P; int n, k; int pow; Declaration // Base addresses of A and P // Lengths of arrays A and B // Return value from power function // Task of main function P[0] = 1; } k++; // 0th element = A[0]^0 = 1 for (int j = 1; j < n; j++) { k = j; // Current length of array B pow power (A[j], j); newElement(P, k, pow); int power (int a, int b) { int pow= a;
12.14 Zylab 3 - Single Procedure Call Given an array of at least one integer, write a program to create a new array with elements equal to the power of each element in the original array raised to the index, i.e., P[i] = A[i]^i. For this, write two functions that will be called in main function independently. • power o inputs: element (A[i]) and index (1) • task: returns the value of element raised to index (A[i]^i). } • newElement o inputs: base address of new array P (*P), current size of P (variable k) and the new element (A[i]^i) • task: add the new element at the end. o This function does not return any value (void). Following is a sample C code to perform the required task. You may modify the code for the functions, but the task performed should not be changed. int main() { // Variable int *A, *P; int n, k; int pow; Declaration // Base addresses of A and P // Lengths of arrays A and B // Return value from power function // Task of main function P[0] = 1; } k++; // 0th element = A[0]^0 = 1 for (int j = 1; j < n; j++) { k = j; // Current length of array B pow power (A[j], j); newElement(P, k, pow); int power (int a, int b) { int pow= a;
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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