The code below serves as a template where the base case and the recursive calls are done. The specific task is to implement the partitioning where elements are either put to the left or right of the pivot depending on their relative values. Input Format The first line contains an integer n, the number of elements in the list. The next n lines would be the unsorted elements of the list. Constraints 1 ≤ n ≤ 10000 Each element i is: -1000 ≤ i ≤ 1000 Minimize auxiliary space usage. Output Format n lines that display the n elements of the sorted list. Smallest element first, largest element last. Example Input 15 3 44 38 5 47 15 36 26 27 2 46 4 19 50 48 Example Output 2 3 4 5 15 19 26 27 36 38 44 46 47 48 50
The code below serves as a template where the base case and the recursive calls are done. The specific task is to implement the partitioning where elements are either put to the left or right of the pivot depending on their relative values. Input Format The first line contains an integer n, the number of elements in the list. The next n lines would be the unsorted elements of the list. Constraints 1 ≤ n ≤ 10000 Each element i is: -1000 ≤ i ≤ 1000 Minimize auxiliary space usage. Output Format n lines that display the n elements of the sorted list. Smallest element first, largest element last. Example Input 15 3 44 38 5 47 15 36 26 27 2 46 4 19 50 48 Example Output 2 3 4 5 15 19 26 27 36 38 44 46 47 48 50
New Perspectives on HTML5, CSS3, and JavaScript
6th Edition
ISBN:9781305503922
Author:Patrick M. Carey
Publisher:Patrick M. Carey
Chapter14: Exploring Object-based Programming: Designing An Online Poker
Section14.1: Visual Overview: Custom Objects, Properties, And Methods
Problem 7QC
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Question
The code below serves as a template where the base case and the recursive calls are done. The specific task is to implement the partitioning where elements are either put to the left or right of the pivot depending on their relative values.
Input Format
The first line contains an integer n, the number of elements in the list. The next n lines would be the unsorted elements of the list.
Constraints
1 ≤ n ≤ 10000
Each element i is: -1000 ≤ i ≤ 1000
Minimize auxiliary space usage.
Output Format
n lines that display the n elements of the sorted list. Smallest element first, largest element last.
Example Input
15
3
44
38
5
47
15
36
26
27
2
46
4
19
50
48
Example Output
2
3
4
5
15
19
26
27
36
38
44
46
47
48
50
![def quick_sort(arr):
# helper function
quick_sort_r(arr, e, len(arr))
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2
3
4.
def quick_sort_r(arr, start, end):
if end - start < 2:
# single element base case
7
8.
return
9.
# choose a pivot
pivot = start
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11
# you may choose other elements
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13
# START CODE FOR PARTITIONING HERE
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15
# END CODE FOR PARTITIONING BEFORE THIS LINE
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# Recursive Calls
# normally you wouldn't need to edit these but you may if want.
quick_sort_r(arr, start, pivot)
quick_sort_r(arr, pivot+1, end)
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21
return
22
# input handling
n = int(input())
arr = []
for i in range(n):
arr.append (int(input()))
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26
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28
# quick sort function call
quick_sort(arr)
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32
# output loop
for i in arr:
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34
print(i)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8a599b3-87f1-4ff4-9cc0-659e59a279d3%2Fa76fa3c7-64ec-4800-81b6-6eea76f225ea%2F3s910txh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:def quick_sort(arr):
# helper function
quick_sort_r(arr, e, len(arr))
1
2
3
4.
def quick_sort_r(arr, start, end):
if end - start < 2:
# single element base case
7
8.
return
9.
# choose a pivot
pivot = start
10
11
# you may choose other elements
12
13
# START CODE FOR PARTITIONING HERE
14
15
# END CODE FOR PARTITIONING BEFORE THIS LINE
16
17
# Recursive Calls
# normally you wouldn't need to edit these but you may if want.
quick_sort_r(arr, start, pivot)
quick_sort_r(arr, pivot+1, end)
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19
20
21
return
22
# input handling
n = int(input())
arr = []
for i in range(n):
arr.append (int(input()))
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25
26
27
28
# quick sort function call
quick_sort(arr)
29
30
31
32
# output loop
for i in arr:
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34
print(i)
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