Python Lee has discovered what he thinks is a clever recursive strategy for printing the elements in a sequence (string, tuple, or list). He reasons that he can get at the first element in a sequence using the 0 index, and he can obtain a sequence of the rest of the elements by slicing from index 1. This strategy is realized in a function that expects just the sequence as an argument. If the sequence is not empty, the first ele
Python
Lee has discovered what he thinks is a clever recursive strategy for printing the elements in a sequence (string, tuple, or list). He reasons that he can get at the first element in a sequence using the 0 index, and he can obtain a sequence of the rest of the elements by slicing from index 1. This strategy is realized in a function that expects just the sequence as an argument. If the sequence is not empty, the first element in the sequence is printed and then a recursive call is executed. On each recursive call, the sequence argument is sliced using the range 1:. Here is Lee’s function definition:
def printAll(seq): if seq: print(seq[0]) printAll(seq[1:])
Write a program that tests this function and add code to trace the argument on each call. Does this function work as expected? If so, are there any hidden costs in running it?
its supposed to print something like this
![f.close()
with open('out.txt', 'r') as f:
f.read()
contents
%3D
assert ("[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]" in contents)
assert ("[1, 2, 3, 4, 5, 6, 7, 8, 9]" in contents)
assert ("[2, 3, 4, 5, 6, 7, 8, 9]" in contents)
assert ("[3, 4, 5, 6, 7, 8, 9]" in contents)
assert ("[4, 5, 6, 7, 8, 9]" in contents)
assert ("[5, 6, 7, 8, 9]" in contents)
assert ("[5, 6, 7, 8, 9]" in contents)
assert ("[6, 7, 8, 9]" in contents)
assert ("[7, 8, 9]" in contents)
assert ("[8, 9]" in contents)
assert ("[9]" in contents)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F241e198c-a29c-4a96-bc4d-989da75da66a%2F4c9d9ecc-1a1f-4de5-bbd3-38d285a4422c%2F3ccf85_processed.jpeg&w=3840&q=75)
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