The freezing point of water is 0.00 °C at 1 atmosphere. How many grams of aluminum sulfate (342.2 g/mol), must be dissolved in 242.0 grams of water to reduce the freezing point by 0.350 °C? Refer to the table for the necessary boiling or freezing point constant. Solvent Diethyl ether Formula Water Ethanol Chloroform CHCl3 Benzene C6H6 Mass= H₂O CH3 CH₂OH Kb (°C/m) Kf(°C/m) 0.512 1.22 3.67 g 2.53 CH3 CH₂ OCH2 CH3 2.02 1.86 1.99 5.12
The freezing point of water is 0.00 °C at 1 atmosphere. How many grams of aluminum sulfate (342.2 g/mol), must be dissolved in 242.0 grams of water to reduce the freezing point by 0.350 °C? Refer to the table for the necessary boiling or freezing point constant. Solvent Diethyl ether Formula Water Ethanol Chloroform CHCl3 Benzene C6H6 Mass= H₂O CH3 CH₂OH Kb (°C/m) Kf(°C/m) 0.512 1.22 3.67 g 2.53 CH3 CH₂ OCH2 CH3 2.02 1.86 1.99 5.12
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:The freezing point of water is 0.00 °C at 1 atmosphere.
**Problem Statement:**
How many grams of aluminum sulfate (342.2 g/mol) must be dissolved in 242.0 grams of water to reduce the freezing point by 0.350 °C? Refer to the table for the necessary boiling or freezing point constant.
**Data Table:**
| Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) |
|----------------|--------------------|-----------------|-----------------|
| Water | \( H_2O \) | 0.512 | 1.86 |
| Ethanol | \( CH_3CH_2OH \) | 1.22 | 1.99 |
| Chloroform | \( CHCl_3 \) | 3.67 | |
| Benzene | \( C_6H_6 \) | 2.53 | 5.12 |
| Diethyl ether | \( CH_3CH_2OCH_2CH_3 \) | 2.02 | |
**Mass of Aluminum Sulfate:**
Mass = _____ g
Expert Solution

Step 1
Given ,
molar mass of aluminium sulfate = 342.2
mass of water = 242.0 g
freezing point reduction
Step by step
Solved in 2 steps
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