please explain The boiling point of water is 100.00 °C at 1 atmosphere.A student dissolves 10.01 grams of zinc sulfate, ZnSO, (161.5 g/mol), in 277.6 grams of water. Use the table of boiling andfreezing point constants to answer the questions below.Kp "C/m) Kf(°C/m)SolventFormulaWaterH2O0.5121.86EthanolCH;CH2OH1.221.99ChloroformCHCI33.67BenzeneCH62.535.12Diethyl ether CH3CH,OCH,CH32.02The molality of the solution is |m.The boiling point of the solution is°C.

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The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 10.01 grams of zinc sulfate, ZnSO, (161.5 g/mol), in 277.6 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Formula K, "C/m) Kf(°C/m) Solvent Water H20 0.512 1.86 Ethanol CH;CH2OH 1.22 1.99 Chloroform CHC1; 3.67 Benzene CH6 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 The molality of the solution is | m. The boiling point of the solution is °C.

The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 10.01 grams of zinc sulfate, ZnSO, (161.5 g/mol), in 277.6 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Formula K, "C/m) Kf(°C/m) Solvent Water H20 0.512 1.86 Ethanol CH;CH2OH 1.22 1.99 Chloroform CHC1; 3.67 Benzene CH6 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 The molality of the solution is | m. The boiling point of the solution is °C.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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